3. top of a surface inclined at 50.0° with height of 10.0 [m], as shown in the figure. The coefficient of kinetic friction between the box and the inclined surface is µk = 0.350. When the box reaches the bottom of the incline, what is A box of mass 20.0 [kg] slides down from the 10.0 (m) the work done by the weight of the box? A0.350 50.0 A. 1.50 [kJ] В. 1.64 [k.J] С. 1.96 (kJ] D. 2.45 [kJ]

3. top of a surface inclined at 50.0° with height of 10.0 [m], as shown in the figure. The coefficient of kinetic friction between the box and the inclined surface is µk = 0.350. When the box reaches the bottom of the incline, what is A box of mass 20.0 [kg] slides down from the 10.0 (m) the work done by the weight of the box? A0.350 50.0 A. 1.50 [kJ] В. 1.64 [k.J] С. 1.96 (kJ] D. 2.45 [kJ]

Name: A box of mass 20.0 [kg] slides down from thetop of a surface inclined
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: A box of mass 20.0 [kg] slides down from thetop of a surface inclined at 50.0° with height of 10.0 [m],as shown in the figure. The coefficient of kinetic frictionbetween the box and the inclined surface is µg = 0.350.28.10.0 (m)When the box reaches

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A 19.1-kg box is being pushed from the bottom to the top of a frictionless ramp. When the box is pushed at a constant velocity, the nonconservative pushing force does 58.0 J of work. How much work is done by the pushing force when the box starts from rest at the bottom and reaches the top of the same ramp with a speed of 1.50 m/s? Wnc = Number i Save for Later Units Attempts: 0 of 1 used Submit Answer
A block of mass m=5 kg is pushed along a rough horizontal table over a distance d=2.8 m by a constant force F of magnitude F= 25 N directed at an angle 0 = 17° below the horizontal as shown in the figure below. The coefficient of kinetic friction between the surface of the table and the block is u = 0.25. Determine the work done on the block by: 1. the applied force: W, app J 2. the normal force: WN = J %3D 3. the gravitational force: W, = 4. the kinetic friction force: Wfr = 5. the net force acting on the block: W, net
5. A person pulls an object of mass 40 kg as far as 20 m above a flat floor at a constant speed. The force used is directed 370 upwards horizontally. The coefficient of kinetic friction of the object with the floor is 0.20. Determine the work by the person, the work by the frictional force, and the total work on the object.
7. A 1650 kg car accelerates up a hill by applying a force of 4.61 × 10³ N parallel to the hill. The hill is at an incline of 13°. m 2016 d = 17 m 13° A. What is the net work done on the car as it travels 17 m up the hill? (Hint: calculate the work done by each force in the system. There are 3 forces. The net work is the sum of the works done by each individual force.) b. What is the change in kinetic energy for the car? at the bottom of the hill. How fast is it moving at the top The car is travelling at a speed of 16 of the hill? I= c) 74°F
1. You push a 67 kg box across a floor where the coefficient of kinetic friction is uk = 0.55. The force you exert is horizontal.(a) How much power is needed to push the box at a speed of 0.50 m/s?(b) How much work do you do if you push the box for 35s? Explain and draws.
Starting from rest, a 6.2-kg block slides 3.2 m down a rough 37-degree incline. The coefficient of kinetic friction between the block and the incline is μk = 0.55. a) Determine the work done by the friction force between block and incline. b) Determine the work done by the normal force. c) Determine the net work done on the block.
2. Use work-energy theorem to solve this problem. A sled (m = 17.2 kg) starts from rest and slides down a hill that is angled at 40.00 above the horizontal. The coefficient of kinetic friction between the hill and the sled is 0.240. The hill is 2.35 m long. A) How much work is done by each force acting on the sled as it slides down the hill? B) How fast is the sled moving at the bottom of the hill? C) If the sled would slide up the hill with the speed found in part B, would the sled travel less than, greater than, or equal to 2.35 m up the hill? Explain. Pictorial Representation Mathematical Representation 4. Aa MacBook Pro DD F10 F8 F9 F2 F5 F6 F7 F3 F4 0/
A 123.0 N carton is pulled up a frictionless baggage ramp inclined at 29.0 degrees above the horizontal by a rope exerting a 70.0 N pull parallel to the ramp's surface. The carton travels 5.00 m along the surface of the ramp. Part A: Calculate the work done on the carton by the rope. Part B: Calculate the work done on the carton by the gravity. Part C: Calculate the work done on the carton by the normal force of the ramp. Part D: What is the net work done on the carton? Part E: Suppose that the rope is angled at 48.4 degrees above the horizontal, instead of being parallel to the ramp's surface. How much work does the rope do on the carton in this case?
Rachael is pulling a 47 kg box up a hill with a 40 degree angle above the horizontal at a constant velocity. The coefficient of kinetic friction between the floor and the box is 0.23. What is the work done on the box by the tension if the box moves up 2.1 m.
1. Mr. Mangan pushes a 90 kg box across a rough surface with a force of 300 N over a displacement of 5 m. The coefficient of kinetic friction between the box and the surface is 0.3. Find the work done by Mr. Mangan, by friction, and the net work.