3. The partial molar volumes of propanone (acetone) and trichloromethane (chloroform) in amixture in which the mole fraction of CHC13 is 0.4693 are 74.166 cm³ mol-i and 80.235 cm3mol-1, respectively. What is the volume of a solution of mass 1.000 kg?4. Discuss the basic thermodynamic concept behind freezing point depression.5. Based from activity 2, summarize and discuss the experimental method by which the freezingpoint of pure acetic acid was determined.00

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3. The partial molar volumes of propanone (acetone) and trichloromethane (chloroform) in a mixture in which the mole fraction of CHCI3 is 0.4693 are 74.166 cm3 mol-1 and 80.235 cm3 mol-1, respectively. What is the volume of a solution of mass 1.000 kg?

3. The partial molar volumes of propanone (acetone) and trichloromethane (chloroform) in a mixture in which the mole fraction of CHCI3 is 0.4693 are 74.166 cm3 mol-1 and 80.235 cm3 mol-1, respectively. What is the volume of a solution of mass 1.000 kg?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

3. The partial molar volumes of propanone (acetone) and trichloromethane (chloroform) in a
mixture in which the mole fraction of CHC13 is 0.4693 are 74.166 cm³ mol-i and 80.235 cm3
mol-1, respectively. What is the volume of a solution of mass 1.000 kg?
4. Discuss the basic thermodynamic concept behind freezing point depression.
5. Based from activity 2, summarize and discuss the experimental method by which the freezing
point of pure acetic acid was determined.
00

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