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3. The graph of the equation below is a circle. x² + 10x + y2 –- 8y – 8 = 0 Evelyn completed the square to find the equation of the circle. Identify the error in her work and explain what she did wrong. Then complete the problem correctly and identify the center and radius of the circle. Step 0: Step 1: Step 2: Step 3: Step 4: Step 5: Evelyn's Solution x² + 10x + y² - 8y – 8 = 0 x² + 10x + y² – 8y – 8 + (8) = 0 + (8) x² + 10x + (5²) + y² – 8y + (4²) = 8 x2 + 10x + 25 + y² – 8y + 16 = 8 (x² + 10x + 25) + (y² – 8y + 16) = 8 (x + 5)² + (y – 4)² = 8

3. The graph of the equation below is a circle. x² + 10x + y2 –- 8y – 8 = 0 Evelyn completed the square to find the equation of the circle. Identify the error in her work and explain what she did wrong. Then complete the problem correctly and identify the center and radius of the circle. Step 0: Step 1: Step 2: Step 3: Step 4: Step 5: Evelyn's Solution x² + 10x + y² - 8y – 8 = 0 x² + 10x + y² – 8y – 8 + (8) = 0 + (8) x² + 10x + (5²) + y² – 8y + (4²) = 8 x2 + 10x + 25 + y² – 8y + 16 = 8 (x² + 10x + 25) + (y² – 8y + 16) = 8 (x + 5)² + (y – 4)² = 8

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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3. The graph of the equation below is a circle. x² + 10x + y? - 8y – 8 = 0 Evelyn completed the square to find the equation of the circle. Identify the error in her work and explain what she did wrong. Then complete the problem correctly and identify the center and radius of the circle. Step 0: Step 1: Step 2: Step 3: Step 4: Step 5: Evelyn's Solution x2 + 10x + y² – 8y – 8 = 0 x² + 10x + y² – 8y – 8 + (8) = 0 + (8) x2 + 10x + (5²) + y² – 8y + (4²) = 8 x² + 10x + 25 + y² – 8y + 16 = 8 (x² + 10x + 25) + (y² – 8y +16) = 8 (x + 5)² + (y – 4)² = 8 Level Four: Knowledge Utilization 4. In what quadrant will the circle identified hy the equation stv MacBook Air DII 80 888 F10 F7 F4 FS F2 F3 @ #3 $ & 2 3 4 5 6 W E R Y G K S D C V comman: command * 00
Transcribed Image Text:3. The graph of the equation below is a circle. x² + 10x + y? - 8y – 8 = 0 Evelyn completed the square to find the equation of the circle. Identify the error in her work and explain what she did wrong. Then complete the problem correctly and identify the center and radius of the circle. Step 0: Step 1: Step 2: Step 3: Step 4: Step 5: Evelyn's Solution x2 + 10x + y² – 8y – 8 = 0 x² + 10x + y² – 8y – 8 + (8) = 0 + (8) x2 + 10x + (5²) + y² – 8y + (4²) = 8 x² + 10x + 25 + y² – 8y + 16 = 8 (x² + 10x + 25) + (y² – 8y +16) = 8 (x + 5)² + (y – 4)² = 8 Level Four: Knowledge Utilization 4. In what quadrant will the circle identified hy the equation stv MacBook Air DII 80 888 F10 F7 F4 FS F2 F3 @ #3 $ & 2 3 4 5 6 W E R Y G K S D C V comman: command * 00
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