3. The graph of f is shown below. Evaluate the integral -10 10 -5 f(x) dx f(x by interpreting it in terms of areas. Remember that the area below the curve and above the x-axis is positive and the area below the x-axis and above the curve is considered negative, so the integral represents net area. -10 10 -5- 0 -5- -10 10 4. If f f(x) dx = 6, f f(x) dx = 2, and f, g(x) = -5, find f³₁[2f(x) - 4g(x)]dx.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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3. The graph of f is shown below. Evaluate the integral
10
Lo
-10
by interpreting it in terms of areas.
Remember that the area below the curve and above the x-axis is positive and the area below the x-axis and
above the curve is considered negative, so the integral represents net area.
-10
f(x) dx
-5
10
LO
0
-5-
-10
5
10
4. If f₁ f(x) dx = 6, f f(x) dx = 2, and f3, g(x) = -5, find f₁[2f(x) — 4g(x)]dx.
Transcribed Image Text:3. The graph of f is shown below. Evaluate the integral 10 Lo -10 by interpreting it in terms of areas. Remember that the area below the curve and above the x-axis is positive and the area below the x-axis and above the curve is considered negative, so the integral represents net area. -10 f(x) dx -5 10 LO 0 -5- -10 5 10 4. If f₁ f(x) dx = 6, f f(x) dx = 2, and f3, g(x) = -5, find f₁[2f(x) — 4g(x)]dx.
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