3. The following contingency table includes the frequencies for type of jurisdiction a police officer patrols and whether they believe they have adequate resources to do their job well. The hypothesis that is being tested is: Those who work in urban areas will believe that they have adequate resources to do their job well. Type of Area Rural Urban Total Satisfied with Resources available? Total 70 Yes 30 110 140 250 150 170 320 No 40 1. What is the independent and w

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2 3 4 5 100%
100% - Normal text
1
Rural
Type of Area
Urban
Total
2
1
Arial
2
12
No
3
40
Satisfied with Resources available?
Total
3. The following contingency table includes the frequencies for type of
jurisdiction a police officer patrols and whether they believe they have
adequate resources to do their job well. The hypothesis that is being tested
is: Those who work in urban areas will believe that they have adequate
resources to do their job well.
Yes
BI UA
30
4
250
2 M EXT
/ <FO
70
5
110 140
150 170 320
1. What is the independent and what is the dependent variable, and the total
sample size?
2.
Calculate the cell percentages.
3. Calculate the expected frequencies for each cell in the table.
4. Test the Null Hypothesis. If you reject the Null hypothesis run the correct
measure of association to report the strength of the relationship between the
two variables.
OO
6
B 0
3
7
= = = = -3-
T
E
0 0
Nov 13
Transcribed Image Text:2 3 4 5 100% 100% - Normal text 1 Rural Type of Area Urban Total 2 1 Arial 2 12 No 3 40 Satisfied with Resources available? Total 3. The following contingency table includes the frequencies for type of jurisdiction a police officer patrols and whether they believe they have adequate resources to do their job well. The hypothesis that is being tested is: Those who work in urban areas will believe that they have adequate resources to do their job well. Yes BI UA 30 4 250 2 M EXT / <FO 70 5 110 140 150 170 320 1. What is the independent and what is the dependent variable, and the total sample size? 2. Calculate the cell percentages. 3. Calculate the expected frequencies for each cell in the table. 4. Test the Null Hypothesis. If you reject the Null hypothesis run the correct measure of association to report the strength of the relationship between the two variables. OO 6 B 0 3 7 = = = = -3- T E 0 0 Nov 13
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