3. The exclusive NOR (XNOR) function can be expressed (a + b)' = XNOR(a, b) = Σm(0, 3) as follows:
3. The exclusive NOR (XNOR) function can be expressed (a + b)' = XNOR(a, b) = Σm(0, 3) as follows:
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please answer part 3d
![(d) Use Boolean algebra to show that the canonical SOP and POS expressions are
equal.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9ea0e50e-bc61-40aa-a108-fd1d63d4d69b%2F2e9b105f-2613-4029-8324-dd6a84a01f60%2Fmg0jd0d_processed.png&w=3840&q=75)
Transcribed Image Text:(d) Use Boolean algebra to show that the canonical SOP and POS expressions are
equal.
![3. The exclusive NOR (XNOR) function can be expressed
(a + b)' = XNOR(a, b) = Σm(0, 3)
as follows:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9ea0e50e-bc61-40aa-a108-fd1d63d4d69b%2F2e9b105f-2613-4029-8324-dd6a84a01f60%2Faxak3ip_processed.png&w=3840&q=75)
Transcribed Image Text:3. The exclusive NOR (XNOR) function can be expressed
(a + b)' = XNOR(a, b) = Σm(0, 3)
as follows:
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
In Canonical SOP form, each product term contains all the literals.
In Canonical POS form, each SUM term contains all the literals.
Step by step
Solved in 2 steps with 3 images
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