3. The cost in dollars to produce x hundreds of nails is given by C(x)=x²-12x+41. What is the minimum cost, and how many nails must be produced for minimum cost? Watch your units! quantity: C cost: 4. The profit equation, in dollars, for a business is P(x)=-4x² +400x-1000 where x is the number of cabinets sold. What is the maximum profit, and how many cabinets should be marketed and sold to get that profit? # cabinets: Max profit: 5. A profit function is given by P(x)=-x²+25x-100, where x is the number of pounds of a product sold, and profit is in dollars. a) Find the maximum profit, and the number of pounds that must be sold for maximum profit. # pounds: Max profit: b) Find the number of pounds of the product that must be sold to breakeven. or pounds

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Educational Content on Profit Functions**

This document contains exercises related to profit functions and their application in business scenarios. Here is a breakdown of the questions and solutions provided:

---

**3. Cost Function for Producing Products**

The cost to produce hundreds of nails is given by the function:

\[ C(x) = x^2 - 12x + 41 \]

where \( x \) is the number of hundreds of nails. 

- **Objective:** Determine the minimum cost and how many nails must be produced to achieve this cost.
  
**Key Steps:**

- **Expression Analysis:** This quadratic function can be used to find the minimum point by applying vertex formulas or completing the square.
- **Results:** The minimum cost and corresponding nail quantity are not filled in but are crucial for understanding cost efficiency.

---

**4. Profit Equations for a Business**

The profit equation in dollars for a business is expressed as:

\[ P(x) = -4x^2 + 400x - 1000 \]

where \( x \) is the number of cabinets sold.

- **Objective:** Identify the maximum profit and the number of cabinets that should be marketed and sold to obtain this profit.

**Key Steps:**

- **Expression Analysis:** This is a downward-opening parabola; find the vertex to determine maximum profit.
- **Quantity & Cost:** The placeholders suggest filling in specific answers: 
  - Quantity: ___
  - Cost: ___
  - Max Profit: ___
  - Cabinets (#): 50

---

**5. Profit Function Related to Product Sales**

A profit function is defined by:

\[ P(x) = x^2 + 25x - 100 \]

where \( x \) is the number of pounds of a product sold, and \( P \) is the profit in dollars.

- **Objectives:**
  - **Find the maximum profit** and the number of pounds that must be sold to achieve it.
  - **Determine the number of pounds required to breakeven**, where profit equals zero.

**Key Steps:** 

- **Expression Analysis:** This mirrors scenarios in maximizing or minimizing quadratics by finding vertex for max profit or solving the equation for zeros to determine breakeven points.
- **Results:** 
  - Pounds for max: ___
  - Max Profit: ___
  - Pounds for breakeven: ___ or ___

---

These exercises are designed to build skills in analyzing quadratic equations as they relate
Transcribed Image Text:**Educational Content on Profit Functions** This document contains exercises related to profit functions and their application in business scenarios. Here is a breakdown of the questions and solutions provided: --- **3. Cost Function for Producing Products** The cost to produce hundreds of nails is given by the function: \[ C(x) = x^2 - 12x + 41 \] where \( x \) is the number of hundreds of nails. - **Objective:** Determine the minimum cost and how many nails must be produced to achieve this cost. **Key Steps:** - **Expression Analysis:** This quadratic function can be used to find the minimum point by applying vertex formulas or completing the square. - **Results:** The minimum cost and corresponding nail quantity are not filled in but are crucial for understanding cost efficiency. --- **4. Profit Equations for a Business** The profit equation in dollars for a business is expressed as: \[ P(x) = -4x^2 + 400x - 1000 \] where \( x \) is the number of cabinets sold. - **Objective:** Identify the maximum profit and the number of cabinets that should be marketed and sold to obtain this profit. **Key Steps:** - **Expression Analysis:** This is a downward-opening parabola; find the vertex to determine maximum profit. - **Quantity & Cost:** The placeholders suggest filling in specific answers: - Quantity: ___ - Cost: ___ - Max Profit: ___ - Cabinets (#): 50 --- **5. Profit Function Related to Product Sales** A profit function is defined by: \[ P(x) = x^2 + 25x - 100 \] where \( x \) is the number of pounds of a product sold, and \( P \) is the profit in dollars. - **Objectives:** - **Find the maximum profit** and the number of pounds that must be sold to achieve it. - **Determine the number of pounds required to breakeven**, where profit equals zero. **Key Steps:** - **Expression Analysis:** This mirrors scenarios in maximizing or minimizing quadratics by finding vertex for max profit or solving the equation for zeros to determine breakeven points. - **Results:** - Pounds for max: ___ - Max Profit: ___ - Pounds for breakeven: ___ or ___ --- These exercises are designed to build skills in analyzing quadratic equations as they relate
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