3. The batteries shown in the circuit below have negligibly small internal resistances. Find the current through(a) the 30.02 resistor; I0.333 A20.0 (b) the 20.02 resistor; andI = 0.250 A10.0 V30.0Ω5.00 V(c) the 10.0 V battery. I= 0.583 A4. A 1.50 μF capacitor is charging through a 12.02 resistor using a 10.0 V battery. What will be the current whenthe capacitor has acquired 1/4 of its maximum charge? I = 0.625A

Answered: Image /qna-images/answer/cb011fee-2b8e-46c1-96c7-00863b379c05.jpg

3. The batteries shown in the circuit below have negligibly small internal resistances. Find the current through (a) the 30.02 resistor; I 0.333 A (b) the 20.02 resistor; and I = 0.250 A (c) the 10.0 V battery. I = 0.583 A 10.0 V 30.0 Ω 20.0 5.00 V 4. A 1.50 µF capacitor is charging through a 12.02 resistor using a 10.0 V battery. What will be the current when the capacitor has acquired 1/4 of its maximum charge? I = 0.625A

3. The batteries shown in the circuit below have negligibly small internal resistances. Find the current through (a) the 30.02 resistor; I 0.333 A (b) the 20.02 resistor; and I = 0.250 A (c) the 10.0 V battery. I = 0.583 A 10.0 V 30.0 Ω 20.0 5.00 V 4. A 1.50 µF capacitor is charging through a 12.02 resistor using a 10.0 V battery. What will be the current when the capacitor has acquired 1/4 of its maximum charge? I = 0.625A

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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