3. The 300-kg gear has a radius of gyration about its center of mass O of ko=400 mm. If the wheel is subjected to a couple moment of M= 300 N-m, determine its angular velocity 6 s after it starts from rest and no slipping occurs. Also determine the friction force that the ground applies to the wheel. Solve the problem using Impulse and Momentum. M 300 Nm 0.6 m

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### Rotational Dynamics Problem

**Problem Statement:**
The 300-kg gear has a radius of gyration about its center of mass \( O \) of \( k_O = 400 \) mm. If the wheel is subjected to a couple moment of \( M = 300 \) N·m, determine its angular velocity 6 seconds after it starts from rest and no slipping occurs. Also determine the friction force that the ground applies to the wheel. Solve the problem using Impulse and Momentum.

**Figure Explanation:**
The provided diagram shows a gear placed on the ground subjected to a couple moment \( M = 300 \) N·m, which is causing it to rotate. The following key measurements and values are illustrated:
- The moment \( M = 300 \) N·m is applied to the gear.
- The radius of the gear is labeled as 0.6 meters.
- The center of mass \( O \) is centered in the middle of the gear.
- The radius of gyration \( k_O \) about its center of mass \( O \) is 400 mm (0.4 meters).

**Objectives:**
1. **Determine the Angular Velocity:**
   - We aim to calculate the angular velocity of the gear after 6 seconds from rest using the principles of impulse and momentum.
   - Given data and formula usage will be applied to find the angular velocity.

2. **Determine the Friction Force:**
   - Assess the friction force that prevents slipping and calculate the magnitude of this force.

### Solutions Approach:
Using the principles of impulse and momentum for rotational systems, we will derive the angular velocity and the friction force. Here's an outline of the approach:

#### Step 1: Convert Units
- Radius of gyration \( k_O = 0.4 \) meters.

#### Step 2: Calculate the Moment of Inertia
- Use \( I_O = m \cdot k_O^2 \) where \( m = 300 \) kg.
- \( I_O = 300 \cdot (0.4)^2 = 300 \cdot 0.16 = 48 \) kg·m\(^2\)

#### Step 3: Apply Impulse and Momentum Principles
- Calculate the angular impulse provided: \( M \cdot t = 300 \cdot 6 = 1800 \) N·m·s
- Angular impulse is equal to
Transcribed Image Text:### Rotational Dynamics Problem **Problem Statement:** The 300-kg gear has a radius of gyration about its center of mass \( O \) of \( k_O = 400 \) mm. If the wheel is subjected to a couple moment of \( M = 300 \) N·m, determine its angular velocity 6 seconds after it starts from rest and no slipping occurs. Also determine the friction force that the ground applies to the wheel. Solve the problem using Impulse and Momentum. **Figure Explanation:** The provided diagram shows a gear placed on the ground subjected to a couple moment \( M = 300 \) N·m, which is causing it to rotate. The following key measurements and values are illustrated: - The moment \( M = 300 \) N·m is applied to the gear. - The radius of the gear is labeled as 0.6 meters. - The center of mass \( O \) is centered in the middle of the gear. - The radius of gyration \( k_O \) about its center of mass \( O \) is 400 mm (0.4 meters). **Objectives:** 1. **Determine the Angular Velocity:** - We aim to calculate the angular velocity of the gear after 6 seconds from rest using the principles of impulse and momentum. - Given data and formula usage will be applied to find the angular velocity. 2. **Determine the Friction Force:** - Assess the friction force that prevents slipping and calculate the magnitude of this force. ### Solutions Approach: Using the principles of impulse and momentum for rotational systems, we will derive the angular velocity and the friction force. Here's an outline of the approach: #### Step 1: Convert Units - Radius of gyration \( k_O = 0.4 \) meters. #### Step 2: Calculate the Moment of Inertia - Use \( I_O = m \cdot k_O^2 \) where \( m = 300 \) kg. - \( I_O = 300 \cdot (0.4)^2 = 300 \cdot 0.16 = 48 \) kg·m\(^2\) #### Step 3: Apply Impulse and Momentum Principles - Calculate the angular impulse provided: \( M \cdot t = 300 \cdot 6 = 1800 \) N·m·s - Angular impulse is equal to
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