I found the intersections which are -1, 0 and 1. There is also an obvious symmetry in the graph. How do I find the area enclosed tho? Is it one of the Type I / Type II Regions? 3. [Straifgtforward]Find the area enclosed by the two curves:y = sin(x/2);Hint: Where do these two curves intersect?(Somewhat tricky; make sure to find all three intersections.)Hint: Sketch the region of interest...Hint: Is there an obvious symmetry? Simplify the region of integration.X = sin(Ty/2).

Answered: 3. [Straifgtforward] Find the area…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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I found the intersections which are -1, 0 and 1. There is also an obvious symmetry in the graph. How do I find the area enclosed tho? Is it one of the Type I / Type II Regions?

3. [Straifgtforward]
Find the area enclosed by the two curves:
y = sin(x/2);
Hint: Where do these two curves intersect?
(Somewhat tricky; make sure to find all three intersections.)
Hint: Sketch the region of interest...
Hint: Is there an obvious symmetry? Simplify the region of integration.
X = sin(Ty/2).

Expert Solution

Step 1: find out point of intersection of two curves and associated common region

Noted that here both are sine curve one along x axis and other along y axis.

here two loop 1st and 3rd quadrant represent required region. From here it is seen that points of intersection of two given curves are $left parenthesis 0 comma 0 right parenthesis comma left parenthesis 1 comma 1 right parenthesis space a n d space left parenthesis negative 1 comma negative 1 right parenthesis$ . Noted that here graph is symmetric about origin.