3. Solve the IVP problem of Dirac's Delta function: y"+3y'+2y = 10 (sin t +d(t-1)); y(0)=0, y'(0)=-1 Note: d is 'delta' in Greek character O y = -2e^(-2t) + 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+1) - e^(-2(t-1))] y = -2e^(-2t) + 6e^(-t-3) cos t + sin t + 10 u(t-1) [e^(-t+1) - e^(-2(t-1))] O y = -2e^(-2t) - 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+1) - e^(-2(t-1))]
3. Solve the IVP problem of Dirac's Delta function: y"+3y'+2y = 10 (sin t +d(t-1)); y(0)=0, y'(0)=-1 Note: d is 'delta' in Greek character O y = -2e^(-2t) + 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+1) - e^(-2(t-1))] y = -2e^(-2t) + 6e^(-t-3) cos t + sin t + 10 u(t-1) [e^(-t+1) - e^(-2(t-1))] O y = -2e^(-2t) - 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+1) - e^(-2(t-1))]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![3. Solve the IVP problem of Dirac's Delta function:
y"+3y'+2y = 10 (sin t +d(t-1)); y(0)=0, y'(0)=-1
Note: d is 'delta' in Greek character
O y = -2e^(-2t) + 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+1) - e^(-2(t-1))]
y = -2e^(-2t) + 6e^(-t-3) cos t + sin t + 10 u(t-1) [e^(-t+1) - e^(-2(t-1))]
O y = -2e^(-2t) - 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+ 1) - e^(-2(t-1)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F982753e9-b749-4c03-b172-eee96c5f8e59%2F282fa125-1674-4f66-b373-4d2d7749dce8%2F424xk69.bmp&w=3840&q=75)
Transcribed Image Text:3. Solve the IVP problem of Dirac's Delta function:
y"+3y'+2y = 10 (sin t +d(t-1)); y(0)=0, y'(0)=-1
Note: d is 'delta' in Greek character
O y = -2e^(-2t) + 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+1) - e^(-2(t-1))]
y = -2e^(-2t) + 6e^(-t-3) cos t + sin t + 10 u(t-1) [e^(-t+1) - e^(-2(t-1))]
O y = -2e^(-2t) - 6e^(-t-3) cos t + sin t - 10 u(t-1) [e^(-t+ 1) - e^(-2(t-1)]
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