3. Show that if X-ty to a constant morphiam in a connected category, then there exist's a unique constant morphism Y. → Y such that hof=f.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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3. Show that if X-fry
in a connected
category
constant morphism Y
is a constant morphion
morphion
then there exists a unique
h
Y
>Y such that hof-f
Transcribed Image Text:3. Show that if X-fry in a connected category constant morphism Y is a constant morphion morphion then there exists a unique h Y >Y such that hof-f
Expert Solution
Step 1: Let's break it down step by step

To show this, let's break it down step by step:

1. Constant Morphism: In a category, a morphism f:XY is called constant if for any objects A and B in the category, the composition fg=f for any morphism g:AX.

2. Connected Category: A category is called connected if for any two objects A and B in the category, there exists at least one morphism f:AB.

Now, let's proving the statement:

Given XfY is a constant morphism in a connected category, it wants to show that there exists a unique constant morphism YhY such that hf=f.

Since XfY is a constant morphism, for any object A in the category, we have fg=f for any morphism g:AX.

Now, consider the identity morphism idY:YY. Since the category is connected, there exists at least one morphism g:YX.


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