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3. Prove from first principles that the following sequences converge. (Hint: your first job is to figure out, informally, what the limit is in each case.) an = Cn = n+1 n+ 2' { 400/n -1/(400m²) n odd n even " 0 bn = dn = 5n 4n²-3' { "/(1+ 7 n/(1+n²) 1≤ n ≤ 900 n> 901

3. Prove from first principles that the following sequences converge. (Hint: your first job is to figure out, informally, what the limit is in each case.) an = Cn = n+1 n+ 2' { 400/n -1/(400m²) n odd n even " 0 bn = dn = 5n 4n²-3' { "/(1+ 7 n/(1+n²) 1≤ n ≤ 900 n> 901

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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3. Prove from first principles that the following sequences converge. (Hint: your first job is to figure out, informally, what the limit is in each case.) an = Cn = n+1 n+ 2' { n odd 400/n -1/(400m²) n even " 0 bn = dn = 5n 4n²-3' { "/(1+ 7 n/(1+n²) 1≤n ≤ 900 n> 901
Transcribed Image Text:3. Prove from first principles that the following sequences converge. (Hint: your first job is to figure out, informally, what the limit is in each case.) an = Cn = n+1 n+ 2' { n odd 400/n -1/(400m²) n even " 0 bn = dn = 5n 4n²-3' { "/(1+ 7 n/(1+n²) 1≤n ≤ 900 n> 901
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