3. Precipitate formation provides one means for re- covering precious metal ions from waste water. For ex- ample, silver ion (Ag*) can be recovered by precipita- tion as silver chloride (AgCI). The net ionic equation for this reaction is shown in Equation 7. Ag*(aq) + cr(aq)→ AgCI(s) (Eq. 7) -> (1) What volume, in milliliters, of 8.75 x10-2M sodium chloride solution (NaCI) would be required to completely precipitate the Ag* ion from one liter of waste water that is 9.00 x 10 M in Ag* lon? (2) Calculate the theoretical yield, in grams, of this procedure. (3) What mass of AgCl would be collected if the percent yield of this precipitation ware 85%?

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3. Precipitate formation provides one means for re-
covering precious metal lons from waste water. For ex-
ample, silver ion (Ag*) can be recovered by precipita-
tion as silver chloride (AgCI). The net ionic equation
for this reaction is shown in Equation 7.
Ag*(aq) + Cr(aq) → A9CI(s)
(Eq. 7)
(1) What volume, in milliliters, of 8.75 x10-2M
sodium chloride solution (NaCI) would be required to
completely precipitate the Ag* ion from ane liter of
waste water that is 9.00 x 10 M in Ag* lon?
(2) Calculate the theoretical yield, in grams, of
this procedure.
(3)
percent yield of this precipitation were 85%7
What mass of AgCl would be collected if the
Transcribed Image Text:3. Precipitate formation provides one means for re- covering precious metal lons from waste water. For ex- ample, silver ion (Ag*) can be recovered by precipita- tion as silver chloride (AgCI). The net ionic equation for this reaction is shown in Equation 7. Ag*(aq) + Cr(aq) → A9CI(s) (Eq. 7) (1) What volume, in milliliters, of 8.75 x10-2M sodium chloride solution (NaCI) would be required to completely precipitate the Ag* ion from ane liter of waste water that is 9.00 x 10 M in Ag* lon? (2) Calculate the theoretical yield, in grams, of this procedure. (3) percent yield of this precipitation were 85%7 What mass of AgCl would be collected if the
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