3. Point P-(1,2) partitions the segment from E3(9,6) to F in a 2:5 ratio. Find the coordinates of point F.

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Chapter87: An Introduction To G- And M-codes For Cnc Programming
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Problem 23A: Write a G-code program for the counterclockwise arc with starting point (-40, -20), ending point...
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**Problem Statement:**

3. Point \( P = (1,2) \) partitions the segment from \( E = (9,6) \) to \( F \) in a 2:5 ratio. Find the coordinates of point \( F \).

**Explanation for Better Understanding:**

To find the coordinates of point \( F \), we need to use the section formula which helps in determining the coordinates of a point that divides a line segment internally in a certain ratio. 

- Given coordinates:
  - \( P=(1,2) \)
  - \( E=(9,6) \)
- Given ratio: \( 2:5 \)

Let \( F = (x,y) \).
  
Using the section formula for internal division, for a point \( P \) dividing the line segment \( EF \) in the ratio \( m:n \), the coordinates are given by:
\[ P = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \]

Here:
- \( P \) is the point dividing the segment \( EF \)
- \( m \) is 2 (the first part of the given ratio)
- \( n \) is 5 (the second part of the given ratio)
- \( E = (x_1, y_1) = (9, 6) \)
- \( F = (x_2, y_2) = (x, y) \)
- Coordinates of \( P = \left( \frac{5x + 2*9}{5+2}, \frac{5y + 2*6}{5+2} \right) = (1,2) \)

Setting up the equations:
\[ \frac{5x + 18}{7} = 1 \]
\[ \frac{5y + 12}{7} = 2 \]

Solving for \( x \):
\[ 5x + 18 = 7 \]
\[ 5x = -11 \]
\[ x = -\frac{11}{5} \]

Solving for \( y \):
\[ 5y + 12 = 14 \]
\[ 5y = 2 \]
\[ y = \frac{2}{5} \]

Therefore, the coordinates of point \( F \) are \( \
Transcribed Image Text:**Problem Statement:** 3. Point \( P = (1,2) \) partitions the segment from \( E = (9,6) \) to \( F \) in a 2:5 ratio. Find the coordinates of point \( F \). **Explanation for Better Understanding:** To find the coordinates of point \( F \), we need to use the section formula which helps in determining the coordinates of a point that divides a line segment internally in a certain ratio. - Given coordinates: - \( P=(1,2) \) - \( E=(9,6) \) - Given ratio: \( 2:5 \) Let \( F = (x,y) \). Using the section formula for internal division, for a point \( P \) dividing the line segment \( EF \) in the ratio \( m:n \), the coordinates are given by: \[ P = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \] Here: - \( P \) is the point dividing the segment \( EF \) - \( m \) is 2 (the first part of the given ratio) - \( n \) is 5 (the second part of the given ratio) - \( E = (x_1, y_1) = (9, 6) \) - \( F = (x_2, y_2) = (x, y) \) - Coordinates of \( P = \left( \frac{5x + 2*9}{5+2}, \frac{5y + 2*6}{5+2} \right) = (1,2) \) Setting up the equations: \[ \frac{5x + 18}{7} = 1 \] \[ \frac{5y + 12}{7} = 2 \] Solving for \( x \): \[ 5x + 18 = 7 \] \[ 5x = -11 \] \[ x = -\frac{11}{5} \] Solving for \( y \): \[ 5y + 12 = 14 \] \[ 5y = 2 \] \[ y = \frac{2}{5} \] Therefore, the coordinates of point \( F \) are \( \
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