3. One mole of ideal gas undergoes an isothermal expansion at 300 K from 1.00 atm to a final pressure when performing 200 J of expansion work. Calculate the final pressure of the gas if the external pressure is 0.2 atm.
3. One mole of ideal gas undergoes an isothermal expansion at 300 K from 1.00 atm to a final pressure when performing 200 J of expansion work. Calculate the final pressure of the gas if the external pressure is 0.2 atm.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![3.
One mole of ideal gas undergoes an isothermal expansion at 300 k from 1.00
atm to a final pressure when performing 200 J of expansion work. Calculate
the final pressure of the gas if the external pressure is 0.2 atm.
- isothermal
- T = 300k
n=1
- P₁ =1.00 atm
- 200 g expansion work
Pext =ozarm
PV = nRT
V₂ =
= constant T & Pext = irreversible { W= Pext AV
W
о рекич
ext
AV
24.6
Pext
V₁ -24.6L 2007
• V₁ = ART
P
。2 atm
=
2007
To V₁ = 1met (₁08206 fmchmer) (3004)
1.00 Eston
2008
VF-24.6
(U-24.62). 2atm = 200
1 atmL = 101.3J 2005, latm. L
101.37
24₁6₁1 V₂ = 1.974 6th L
P](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7cbbd39-e240-400c-aa00-3c97351af073%2F7137e07b-17a3-490a-bcb5-ed947546d07c%2Fc7nf8fe_processed.png&w=3840&q=75)
Transcribed Image Text:3.
One mole of ideal gas undergoes an isothermal expansion at 300 k from 1.00
atm to a final pressure when performing 200 J of expansion work. Calculate
the final pressure of the gas if the external pressure is 0.2 atm.
- isothermal
- T = 300k
n=1
- P₁ =1.00 atm
- 200 g expansion work
Pext =ozarm
PV = nRT
V₂ =
= constant T & Pext = irreversible { W= Pext AV
W
о рекич
ext
AV
24.6
Pext
V₁ -24.6L 2007
• V₁ = ART
P
。2 atm
=
2007
To V₁ = 1met (₁08206 fmchmer) (3004)
1.00 Eston
2008
VF-24.6
(U-24.62). 2atm = 200
1 atmL = 101.3J 2005, latm. L
101.37
24₁6₁1 V₂ = 1.974 6th L
P
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