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3. On page 9 of chapter 8 notes, you are asked to finish some parts of a full 5-step hypothesis test. What are the degrees of freedom for this problem? O о O O 59 34 35 36 58

3. On page 9 of chapter 8 notes, you are asked to finish some parts of a full 5-step hypothesis test. What are the degrees of freedom for this problem? O о O O 59 34 35 36 58

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question is in reference to the notes attached. Help appreciated, thanks

3. On page 9 of chapter 8 notes, you are asked to finish some parts of a full 5-step hypothesis test. What are the degrees of freedom for this problem? O о O O 59 34 35 36 58
Transcribed Image Text:3. On page 9 of chapter 8 notes, you are asked to finish some parts of a full 5-step hypothesis test. What are the degrees of freedom for this problem? O о O O 59 34 35 36 58
Step 1: The claim that "blue enhances performance on a creative task" can be restated as "people with a blue background (group 2) have a higher mean creativity score than those in the group with a red background (group 1)". This can be expressed as µ₁ < µ2. Since both sample sizes are above n = 30, so normality is met. Step 2: The hypotheses can be written as: Step 3: Because we have two independent samples and we are testing a claim about two population means, we use a t distribution. Step 3: continued, Calculate the test statistic (x₂-x₂)(14₂₁-14₂) | $²__ $²2² + t = df = Vn₂ m₂ m H₁:1₁ = 4₂ 0 H₁:1₁<H₂ Step 4: The p-value = (3.39-3.97)-0 0.97² 0.63² 35 36 + = -2.979 (This p-value is also equal to the ar to the left of the test statistic of t= -2.979.) Since this is less than the significance level of 0.01, we reject the null hypothesis. Step 5: There is sufficient evidence to support the claim that the red background group has a lower mean creativity score than the blue background group.
Transcribed Image Text:Step 1: The claim that "blue enhances performance on a creative task" can be restated as "people with a blue background (group 2) have a higher mean creativity score than those in the group with a red background (group 1)". This can be expressed as µ₁ < µ2. Since both sample sizes are above n = 30, so normality is met. Step 2: The hypotheses can be written as: Step 3: Because we have two independent samples and we are testing a claim about two population means, we use a t distribution. Step 3: continued, Calculate the test statistic (x₂-x₂)(14₂₁-14₂) | $²__ $²2² + t = df = Vn₂ m₂ m H₁:1₁ = 4₂ 0 H₁:1₁<H₂ Step 4: The p-value = (3.39-3.97)-0 0.97² 0.63² 35 36 + = -2.979 (This p-value is also equal to the ar to the left of the test statistic of t= -2.979.) Since this is less than the significance level of 0.01, we reject the null hypothesis. Step 5: There is sufficient evidence to support the claim that the red background group has a lower mean creativity score than the blue background group.
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