3. Number of monthly absences of Juan Dela Cruz based on his previous records ofabsences as presented in the probability distribution below.Percent P(x)Number of Absences (X)325%430%30%6.15%

Expected value : Expected value is that the value that AN investment is foreseen to own at a while…

Answered: 3. Number of monthly absences of Juan…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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2. Graph each distribution using a probability histogram. a) P(x) b) P(x) 0.05 1 12 4 0.13 5 12 1 6. 0.24 8. 0.38 1 3 10 0.12 1 12 0.05 3 14 0.03
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
In how many ways can all of the letters in the word ISOSCELES be arranged if the arrangement must: a) start with E and end with E b) Have S for the middle letter c) have the vowels togrther d) have the consonants together e) ha ve the consonants and vowels alternate
Nicole has purchased the life insurance policy for her fish for the price of $200 per year and Nicole will receive $4000 in case if her fish passes away. The insurance company estimated the probability of her fish passing away during the length of the policy to be 0.5%. Let XX be the insurance company's profit. Answer the following questions: 1. Create the probability distribution table for XX : XX outcome profit xx ,$ P(X=x)P(X=x) fish passes away fish survives 2. Use the probability distribution table to find the following: E[X]=μX=E[X]=μX= dollars. (Round the answer to 1 decimal place.) SD[X]=σX=SD[X]=σX= dollars. (Round the answer to 1 decimal place.)
Megan has purchased the insurance policy from an insurance company to cover the value of hers new car in case if it gets totaled for the price of $1500 per year. Megan's car worth $20000 and the probability of her totaling the car during the length of the policy is estimated to be 0.4%. Let XX be the insurance company's profit. Answer the following questions: 1. Create the probability distribution table for XX : XX outcome profit xx ,$ P(X=x)P(X=x) car is totaled car is not totaled 2. Use the probability distribution table to find the following: E[X]=μX=E[X]=μX= dollars. (Round the answer to 1 decimal place.) SD[X]=σX=SD[X]=σX= dollars. (Round the answer to 1 decimal place.)
3
15. During a recent period of high unemployment, hundreds of thousands of drivers dropped their automobile insurance. Sample data representative of the national automobile insur- ance coverage for individuals 18 years of age and older are shown here. b. C. Age 18 to 34 35 and over 60 Automobile Insurance Yes 1500 1900 a. Develop a joint probability table for these data and use the table to answer the remaining questions. No 340 260 What do the marginal probabilities tell you about the age of the U.S. population? What is the probability that a randomly selected individual does not have automobile insurance coverage? d. If the individual is between the ages of 18 and 34, what is the probability that the individual does not have automobile insurance coverage? e. If the individual is age 35 or over, what is the probability that the individual does not have automobile insurance coverage? f. If the individual does not have automobile insurance, what is the probability that the individual is…
A survey of almost 44,000 two-child families yielded the accompanying table. The probability distribution of x, the number of boys in a two-child family is given below. Find E(x) and give a practical interpretation of its value. Gender Configuration Proportion D Girl-girl (GG) Boy-girl (BG) Girl-Boy (GB) 0.215 0.267 0.256 P(x) 0.215 0.523 0.262 Boy-boy (BB) 0.262 Choose the correct answer below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) O A. If a very large number of households were sampled, on average, there would be E(x) = boys. O B. If a very large number of two-child households were sampled, on average, there would be E(x) = boys. of getting a family with a boy. %3D O C. If a very large number of two-child households were sampled, there would be a probability of E(x) = O D. In the sample of 44,000 households, each household had E(x) = boys.

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3. Number of monthly absences of Juan Dela Cruz based on his previous records of absences as presented in the probability distribution below. Percent P(x) Number of Absences (X) 3 25% 4 30% 30% 6. 15%