3. Normal Distribution and Z - ScoresAssume a normal distribution for a population of scores for a standardized exam.The average exam score is 70, and the standard deviation is 5. Jeff's exam score is63.a) What percentage of the population has an exam score greater than Jeff's?b) What percentage of the population has an exam score greater than Jeff's butless than the score of 74?c)If 10,000 people were given the exam, how many of them have an exam scoreless than Jeff's?

The question is about normal dist. Given : Popl. avg. exam score ( μ ) = 70 Popl. std. deviation of…

Answered: 3. Normal Distribution and Z - Scores…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A primary measure of dispersion for sample data is the sample standard deviation, s. Choose the best option to explain what the meaning of the sample standard deviation is, in general. A. The distance between one observation and the mean. B. The average distance of an observation from the middle of the distribution. C. The average distance between observations in the sample. D. The distance between the third and first quartiles.
Which of the following is the value of ?0.05 with a sample size of 10? a. 1.812 b. 1.900 c. 1.860 d. 1.833
In the 1992 presidential election, Alaska's 40 election districts averaged 1993 votes per district for President Clinton. The standard deviation was 584. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( b. Is 1993 a population mean or a sample mean? Select an answer v C. Find the probability that a randomly selected district had fewer than 2053 votes for President Clinton. d. Find the probability that a randomly selected district had between 2074 and 2208 votes for President Clinton. e. Find the 95th percentile for votes for President Clinton. Round your answer to the nearest whole number.
If some data is symmetrical and unimodal, and the mean and standard deviation are 230 and 40 respectively: a)How much of the data lies between 190 and 270 b)How much lies between 150 and 230 c)How much lies between 190 and 310
9. Write the appropriate notation symbol that corresponds to the given parameter or statistic. a. Population Mean: tof births d. Population Standard Deviation: variable? Triplets b. Sample Mean: e. Sample Variance: c. Population Variance: f. Sample Standard Deviation: sihle for the standard deviation of a list of numbers to equal zero?
4. The lowest and the highest data value of a data set are 12 and 28 respectively, then the approximate standard deviation is:
1. The position number w(letter) tells us where in the alphabet the given letter is located. For instance: w("b") = 2. Find the mean, median and population standard deviation for the vowel position numbers in the English alphabet.
10. On a history exam, Roberto had a score of 72, which was exactly 3 standard deviations below the mean. The standard deviation for the exam is 4. a. What score was 2 standard deviations above the mean? b. What percent of the scores were at least 88? 72 c. What score represents the mean? d. What percent of the scores were between 80 and 88?
The average income in a state was $64 comma 64,000 per person per year. Suppose the standard deviation is $29 comma 29,000 and the distribution is right-skewed. Suppose we take a random sample of 100 residents of the state. Complete parts (a) and (b) below. a. What value should we expect for the sample mean? Why? b. What is the standard error for the sample mean?
1. Using a calculator, solve for the mean and the standard deviation of the given set of data. a. 15,18, 16, 17, 21 b. 21,24, 31, 19, 25 C. 84,85, 94, 76, 89 d. 54,66, 51, 37,49
In the 1992 presidential election, Alaska's 40 election districts averaged 1989 votes per district for President Clinton. The standard deviation was 568. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( __ , __ ) b. Is 1989 a population mean or a sample mean? Select an answer _______. c. Find the probability that a randomly selected district had fewer than 2087 votes for President Clinton. _____ d. Find the probability that a randomly selected district had between 1905 and 2194 votes for President Clinton.______ e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number. ______

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