3. meters. The rightmost charge is at x = 2m and has a charge of q =8µC. The leftmost charge is at x = -2m and has a charge of q = -8µC. Two point charges are located on the x axis separated by a distance of 4 a) Which of the following is the correct equation to determine the potential V(x) at any point along the x-axis between the two charges: V(x) = kq/(x+2) + kq/(x-2) V(x) = kq/x + k(-q)/x O V(x) = kq/(x+2+x-2) V(x) = kq1q2/x2 V(x) = k(-q)/(x+2) + kq/(-x+2) b) Based on your answer to question 3 and logical extensions you can draw from it, where is the potential equal to zero for the scenario given in question 3? (Select all that apply) O at x=0m O everywhere except infinity O at positive infinity O at x = 3m O anywhere on the y-axis O anywhere on the x-axis O at negative infinity at x=-3m c) For the scenario given in question 3, which of the following shows the correct equation to solve for the electric field strength at x=0m using Coulomb's Law?
3. meters. The rightmost charge is at x = 2m and has a charge of q =8µC. The leftmost charge is at x = -2m and has a charge of q = -8µC. Two point charges are located on the x axis separated by a distance of 4 a) Which of the following is the correct equation to determine the potential V(x) at any point along the x-axis between the two charges: V(x) = kq/(x+2) + kq/(x-2) V(x) = kq/x + k(-q)/x O V(x) = kq/(x+2+x-2) V(x) = kq1q2/x2 V(x) = k(-q)/(x+2) + kq/(-x+2) b) Based on your answer to question 3 and logical extensions you can draw from it, where is the potential equal to zero for the scenario given in question 3? (Select all that apply) O at x=0m O everywhere except infinity O at positive infinity O at x = 3m O anywhere on the y-axis O anywhere on the x-axis O at negative infinity at x=-3m c) For the scenario given in question 3, which of the following shows the correct equation to solve for the electric field strength at x=0m using Coulomb's Law?
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
Transcribed Image Text:3. Two point charges are located on the x axis separated by a distance of 4
meters. The rightmost charge is at x = 2m and has a charge of q =8µC. The
leftmost charge is at x = -2m and has a charge of q = -8µC.
a) Which of the following is the correct equation to determine the potential V(x)
at any point along the x-axis between the two charges:
O V(x) = kq/(x+2) + kq/(x-2)
O V(x) = kq/x + k(-g)/x
O V(x) = kq/(x+2+x-2)
O V(x) = kq1q2/x²
O V(x) = k(-q)/(x+2) + kq/(-x+2)
b) Based on your answer to question 3 and logical extensions you can draw from
it, where is the potential equal to zero for the scenario given in question 3?
(Select all that apply)
O at x=0m
O everywhere except infinity
O at positive infinity
O at x = 3m
O anywhere on the y-axis
O anywhere on the x-axis
O at negative infinity
at x=-3m
c) For the scenario given in question 3, which of the following shows the correct
equation to solve for the electric field strength at x=0m using Coulomb's
Law?
E(0) =kq/(0+2)2
E(0) =
k(-a)
+
(0+2)
(-0+2)?
E(0) = V(0)/r
E(O) = kq/x?
Ě(0) = A (1) +
서(-9)
(0+2)?
;(-1)
(-0+2)
d)For the scenario given in question 3, what is the potental at x = 1m?
e) For the scenario given in question 3, what is the potental at x = -1m?
f) For the scenario given in question 3, if you weren't told what the position
values or charge values were for the two point charges, but you instead used a
multimeter to measure the potential difference between x=1m and x=-1m and
found that it displayed a value equal to the difference between the potentials
you calculated in questions 5 and 6 (as it would be expected to show), you could
use this information to estimate the electric field strength at x=0m between
them. What would your estimated E(0) be? (Give your answer in units of
Volts/meter, ensuring the sign matches the correct direction of the electric
field).
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