3. M 5.3 5.6 P N 3.4

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Example Problem 3: Triangle with Side Lengths**

In this example problem, we are presented with a triangle labeled \( \triangle MNP \). The vertices of the triangle are marked as \( M \), \( N \), and \( P \).

**Side Lengths:**
- The side \( MN \) has a length of 5.6 units.
- The side \( MP \) has a length of 5.3 units.
- The side \( NP \) has a length of 3.4 units.

To solve triangle-based problems, such as finding the angles using the side lengths, you can apply various rules and formulas, such as:

1. **The Law of Cosines:**

   \[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \]

   where \( a \), \( b \), and \( c \) are the side lengths, and \( C \) is the angle opposite side \( c \).

2. **The Law of Sines:**

   \[ \frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} \]

   where \( a \), \( b \), and \( c \) are the side lengths relative to angles \( A \), \( B \), and \( C \) respectively.

Understanding these fundamentals helps in solving various aspects of triangles, including determining unknown sides and angles.
Transcribed Image Text:**Example Problem 3: Triangle with Side Lengths** In this example problem, we are presented with a triangle labeled \( \triangle MNP \). The vertices of the triangle are marked as \( M \), \( N \), and \( P \). **Side Lengths:** - The side \( MN \) has a length of 5.6 units. - The side \( MP \) has a length of 5.3 units. - The side \( NP \) has a length of 3.4 units. To solve triangle-based problems, such as finding the angles using the side lengths, you can apply various rules and formulas, such as: 1. **The Law of Cosines:** \[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) \] where \( a \), \( b \), and \( c \) are the side lengths, and \( C \) is the angle opposite side \( c \). 2. **The Law of Sines:** \[ \frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)} \] where \( a \), \( b \), and \( c \) are the side lengths relative to angles \( A \), \( B \), and \( C \) respectively. Understanding these fundamentals helps in solving various aspects of triangles, including determining unknown sides and angles.
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