3. log(x) + log(7) = 2 5. 3 log(2x - 1) = 1 Worksheets for Math 05 4. log(x) +5 + 5 = 6.2 6.log(x + 2) + log(5) = 1 Earlier we noted that if m= n, then log(m) = log (n). The converse of the statement is also other words, if log(m) = log (n), then m = n. Although the situation has not arisen in the p examples, we need to check that our answers that determines which value of x is the solutic equation. Logarithms of negative numbers are undefined and not all preliminary answers ar to the original logarithmic equation. These solutions are called extraneous solutions to the equation. Example 7: Solve the equation In(x + 2) + In(x - 2) = In (5).

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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3. log(x) + log(7) = 2
-
5. 3 log(2x − 1) = 1
Example 7:
Worksheets for Math 096
4. log(x) + 5 = 6.2
6.log(x + 2) + log(5) = 1
2
Earlier we noted that if m= n, then log(m) = log (n). The converse of the statement is also true. In
other words, if log(m) = log (n), then m = n. Although the situation has not arisen in the previous
examples, we need to check that our answers that determines which value of x is the solution to th
equation. Logarithms of negative numbers are undefined and not all preliminary answers are solut
to the original logarithmic equation. These solutions are called extraneous solutions to the original
equation.
Solve the equation In(x + 2) + In(x - 2) = ln (5).
Transcribed Image Text:3. log(x) + log(7) = 2 - 5. 3 log(2x − 1) = 1 Example 7: Worksheets for Math 096 4. log(x) + 5 = 6.2 6.log(x + 2) + log(5) = 1 2 Earlier we noted that if m= n, then log(m) = log (n). The converse of the statement is also true. In other words, if log(m) = log (n), then m = n. Although the situation has not arisen in the previous examples, we need to check that our answers that determines which value of x is the solution to th equation. Logarithms of negative numbers are undefined and not all preliminary answers are solut to the original logarithmic equation. These solutions are called extraneous solutions to the original equation. Solve the equation In(x + 2) + In(x - 2) = ln (5).
Example 5:
Step 1:
Step 2:
Step 3:
Example 6:
Step 1:
Step 2:
Step 3:
Step 4:
Solve the equation log(x) - log (7) = 2.
10g (+)-2
==10²-100
X=7·100=700
7
Solve the equation log(2x) + log (5) = 3.
Problem Set C:
Solve and check the following equations:
1. log(3x) + 5 = 6.2
log(C2x) (5))=3
log(10x) = 3
lox=10³ = 1000
X = 1000
10 =100
2. 2 log(3-x) = 1
Transcribed Image Text:Example 5: Step 1: Step 2: Step 3: Example 6: Step 1: Step 2: Step 3: Step 4: Solve the equation log(x) - log (7) = 2. 10g (+)-2 ==10²-100 X=7·100=700 7 Solve the equation log(2x) + log (5) = 3. Problem Set C: Solve and check the following equations: 1. log(3x) + 5 = 6.2 log(C2x) (5))=3 log(10x) = 3 lox=10³ = 1000 X = 1000 10 =100 2. 2 log(3-x) = 1
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