3. log(x) + log(7) = 2-5. 3 log(2x − 1) = 1Example 7:Worksheets for Math 0964. log(x) + 5 = 6.26.log(x + 2) + log(5) = 12Earlier we noted that if m= n, then log(m) = log (n). The converse of the statement is also true. Inother words, if log(m) = log (n), then m = n. Although the situation has not arisen in the previousexamples, we need to check that our answers that determines which value of x is the solution to thequation. Logarithms of negative numbers are undefined and not all preliminary answers are solutto the original logarithmic equation. These solutions are called extraneous solutions to the originalequation.Solve the equation In(x + 2) + In(x - 2) = ln (5). Example 5:Step 1:Step 2:Step 3:Example 6:Step 1:Step 2:Step 3:Step 4:Solve the equation log(x) - log (7) = 2.10g (+)-2==10²-100X=7·100=7007Solve the equation log(2x) + log (5) = 3.Problem Set C:Solve and check the following equations:1. log(3x) + 5 = 6.2log(C2x) (5))=3log(10x) = 3lox=10³ = 1000X = 100010 =1002. 2 log(3-x) = 1

Answered: Image /qna-images/answer/f506d08c-0876-4503-bb8b-d14095e2f9bf.jpg

3. log(x) + log(7) = 2 5. 3 log(2x - 1) = 1 Worksheets for Math 05 4. log(x) +5 + 5 = 6.2 6.log(x + 2) + log(5) = 1 Earlier we noted that if m= n, then log(m) = log (n). The converse of the statement is also other words, if log(m) = log (n), then m = n. Although the situation has not arisen in the p examples, we need to check that our answers that determines which value of x is the solutic equation. Logarithms of negative numbers are undefined and not all preliminary answers ar to the original logarithmic equation. These solutions are called extraneous solutions to the equation. Example 7: Solve the equation In(x + 2) + In(x - 2) = In (5).

3. log(x) + log(7) = 2 5. 3 log(2x - 1) = 1 Worksheets for Math 05 4. log(x) +5 + 5 = 6.2 6.log(x + 2) + log(5) = 1 Earlier we noted that if m= n, then log(m) = log (n). The converse of the statement is also other words, if log(m) = log (n), then m = n. Although the situation has not arisen in the p examples, we need to check that our answers that determines which value of x is the solutic equation. Logarithms of negative numbers are undefined and not all preliminary answers ar to the original logarithmic equation. These solutions are called extraneous solutions to the equation. Example 7: Solve the equation In(x + 2) + In(x - 2) = In (5).

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

3. log(x) + log(7) = 2
-
5. 3 log(2x − 1) = 1
Example 7:
Worksheets for Math 096
4. log(x) + 5 = 6.2
6.log(x + 2) + log(5) = 1
2
Earlier we noted that if m= n, then log(m) = log (n). The converse of the statement is also true. In
other words, if log(m) = log (n), then m = n. Although the situation has not arisen in the previous
examples, we need to check that our answers that determines which value of x is the solution to th
equation. Logarithms of negative numbers are undefined and not all preliminary answers are solut
to the original logarithmic equation. These solutions are called extraneous solutions to the original
equation.
Solve the equation In(x + 2) + In(x - 2) = ln (5).

Example 5:
Step 1:
Step 2:
Step 3:
Example 6:
Step 1:
Step 2:
Step 3:
Step 4:
Solve the equation log(x) - log (7) = 2.
10g (+)-2
==10²-100
X=7·100=700
7
Solve the equation log(2x) + log (5) = 3.
Problem Set C:
Solve and check the following equations:
1. log(3x) + 5 = 6.2
log(C2x) (5))=3
log(10x) = 3
lox=10³ = 1000
X = 1000
10 =100
2. 2 log(3-x) = 1

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