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3. Let X and Y be two independent Poisson random variables with mean 2. Then |A|P[min{X, Y} ≤ 1] = 9e-4 CP[min{X, Y} ≤ 1] = 3e-²(2 − 3e-²) [B] P[min{X, Y} ≤ 1] = (1 - 3e−²)² DP[min{X, Y} ≤ 1] = e−4

3. Let X and Y be two independent Poisson random variables with mean 2. Then |A|P[min{X, Y} ≤ 1] = 9e-4 CP[min{X, Y} ≤ 1] = 3e-²(2 − 3e-²) [B] P[min{X, Y} ≤ 1] = (1 - 3e−²)² DP[min{X, Y} ≤ 1] = e−4

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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3. Let X and Y be two independent Poisson random variables with mean 2. Then |A|P[min{X, Y} ≤ 1] = 9e-4 CP[min{X, Y} ≤ 1] = 3e-²(2 − 3e-²) [B] P[min{X, Y} ≤ 1] = (1 - 3e−²)² DP[min{X, Y} ≤ 1] = e−4
Transcribed Image Text:3. Let X and Y be two independent Poisson random variables with mean 2. Then |A|P[min{X, Y} ≤ 1] = 9e-4 CP[min{X, Y} ≤ 1] = 3e-²(2 − 3e-²) [B] P[min{X, Y} ≤ 1] = (1 - 3e−²)² DP[min{X, Y} ≤ 1] = e−4
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