3. Let LSA(x,b) represent a left arithmetic shift of x by b bits, and RSL(x,b) represent a right logical shift of x by b bits. Using two's complement binary with fixed size of 16 bit, what is the result (in decimal) of the expression LSA(-1610,8) + RSL(-12810,4)? A) 110 XB) -810 C) -11210 D) -66₁10 E) -12810 F) -17210
3. Let LSA(x,b) represent a left arithmetic shift of x by b bits, and RSL(x,b) represent a right logical shift of x by b bits. Using two's complement binary with fixed size of 16 bit, what is the result (in decimal) of the expression LSA(-1610,8) + RSL(-12810,4)? A) 110 XB) -810 C) -11210 D) -66₁10 E) -12810 F) -17210
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![**Problem 3:**
**Description:**
Let LSA(x, b) represent a left arithmetic shift of x by b bits, and RSL(x, b) represent a right logical shift of x by b bits. Using two’s complement binary with a fixed size of 16 bits, determine the resulting decimal value of the following expression:
\[ \text{LSA}(-16_{10}, 8) + \text{RSL}(-128_{10}, 4) \]
**Options:**
A) \( 1_{10} \)
B) \(-8_{10}\)
C) \(-112_{10}\)
D) \(-66_{10}\)
E) \(-128_{10}\)
F) \(-172_{10}\)
**Explanation:**
- **Left Arithmetic Shift (LSA):** Moves all bits to the left by a specified number of positions (b), while preserving the sign bit for the most significant bit.
- **Right Logical Shift (RSL):** Moves all bits to the right by a specified number of positions (b) while filling the vacated bit positions with zeros, regardless of the sign bit.
**Objective:**
Calculate the value in decimal for \( \text{LSA}(-16_{10}, 8) + \text{RSL}(-128_{10}, 4) \) using 16-bit two’s complement representation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F37f4a686-630c-4e5f-a080-44df96b1e6fd%2Ff07dd115-04c6-49c2-bb01-f6df588d43b9%2F0muudfh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 3:**
**Description:**
Let LSA(x, b) represent a left arithmetic shift of x by b bits, and RSL(x, b) represent a right logical shift of x by b bits. Using two’s complement binary with a fixed size of 16 bits, determine the resulting decimal value of the following expression:
\[ \text{LSA}(-16_{10}, 8) + \text{RSL}(-128_{10}, 4) \]
**Options:**
A) \( 1_{10} \)
B) \(-8_{10}\)
C) \(-112_{10}\)
D) \(-66_{10}\)
E) \(-128_{10}\)
F) \(-172_{10}\)
**Explanation:**
- **Left Arithmetic Shift (LSA):** Moves all bits to the left by a specified number of positions (b), while preserving the sign bit for the most significant bit.
- **Right Logical Shift (RSL):** Moves all bits to the right by a specified number of positions (b) while filling the vacated bit positions with zeros, regardless of the sign bit.
**Objective:**
Calculate the value in decimal for \( \text{LSA}(-16_{10}, 8) + \text{RSL}(-128_{10}, 4) \) using 16-bit two’s complement representation.
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