3. In (sec L-10-1ki ])

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 44RE
Question

pls check my solution i dont know where i messed up answer should be -15.31-2.57i

3. In (secE-10-1ki])
sec (-10-16i) = sec(10)cec(ui)
scl (A-B)
It tan Atan B
Ittan (10) tan (ivi)
= Foc (10) wsn(iu)
(H.la)(2.25 X10 )
1 +0.65i
It tan(10)i tamh (16)
Scc (-10 -16i)= -1. 88X107+ 1. 22 X10
(-1-88x10 ")* † (1.22x10")"
r= 2.24 X10-7
Od = tan-
1. 22X10-7
-1.88X10-7
Od = -32, 98'
2.57i
In (2.24X10Te.7")
In (2.24) + mteい
2.57
Od 180-32.98
= 147. 02
%3D
In (ec(-0-liT -15.31 + 2.97i
ora 147.02
= 2.57 rad
(212i)
%3D
CS Scanned with CamScanner
Transcribed Image Text:3. In (secE-10-1ki]) sec (-10-16i) = sec(10)cec(ui) scl (A-B) It tan Atan B Ittan (10) tan (ivi) = Foc (10) wsn(iu) (H.la)(2.25 X10 ) 1 +0.65i It tan(10)i tamh (16) Scc (-10 -16i)= -1. 88X107+ 1. 22 X10 (-1-88x10 ")* † (1.22x10")" r= 2.24 X10-7 Od = tan- 1. 22X10-7 -1.88X10-7 Od = -32, 98' 2.57i In (2.24X10Te.7") In (2.24) + mteい 2.57 Od 180-32.98 = 147. 02 %3D In (ec(-0-liT -15.31 + 2.97i ora 147.02 = 2.57 rad (212i) %3D CS Scanned with CamScanner
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