3. In genetic investigations, one frequently samples from a binomial distribution. Except that observations of x = 0 are impossible; so in fact, the sampling is from the conditional (truncated) distribution: f(x) = (x) 1-(1-p)m p*(1-p) m-x x/1-(1-p)m (1,2....mm) (x) Find the maximum likelihood estimator for p in the case of m= 2 samples of size n. 3

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A:

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Q: x + 5x-80 = 4

A:

Q: Divide x? + 2x – 15 by x + 5.

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Q: -2x + 4 = 7

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Q: Divide showing your work to receive full credit (a* + 45a +18a?) - 9a

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A:

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A: 5a + 7 = 10 Subtract 7 on both side, 5a =3

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A: Given query is to simplify the expression.

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A:

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A: Given,     -7 = 2r + 1         ⇒  2r = -7 -1         ⇒   2r = -8        ⇒     r =  -82

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A: We have to factor 10 so that the sum of the factors = -710= -5 times -2 and -5 + (-2) =-7 too So we…

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Q: V18x+43 3メt=

A:

Q: Evaluate x2 + 5x, for x = 6.

A: x2+5x, x=6

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A: the solution are next step.....

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A: See the solution below:

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A: We need to add

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A: -10 would be correct answar.

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A:

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A:

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A: 2x+6x=8x

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A: The given equation is,