3. In circle J with

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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**Topic: Geometry - Circle and Angles**

**Problem Statement:**

In circle \( J \) with \( \angle HLK = 37^\circ \), find the measure of minor arc \( HK \).

**Diagram Explanation:**

The diagram presents a circle with the center labeled as \( J \). Points \( H \), \( L \), and \( K \) are marked on the circumference of the circle. The angle \( \angle HLK \) is indicated within the circle, intersecting the arc \( HK \).

**Solution Steps:**

To solve the problem, we can use the relationship between the central angle and the arc in a circle. Here are the steps:

1. The angle \( \angle HLK \) is given as \( 37^\circ \).
2. Note that \( \angle HLK \) is the inscribed angle that intercepts the minor arc \( HK \).
3. Recall the property of circles: the measure of an inscribed angle is half the measure of the intercepted arc.
4. Let \( m \) be the measure of the minor arc \( HK \).
5. According to the property: \( \angle HLK = \frac{1}{2} \times m \).
6. Substitute \( \angle HLK = 37^\circ \) into the equation: \( 37^\circ = \frac{1}{2} \times m \).
7. Solve for \( m \): 
   \[
   m = 2 \times 37^\circ 
   \]
   \[
   m = 74^\circ 
   \]

So, the measure of the minor arc \( HK \) is \( 74^\circ \).
Transcribed Image Text:**Topic: Geometry - Circle and Angles** **Problem Statement:** In circle \( J \) with \( \angle HLK = 37^\circ \), find the measure of minor arc \( HK \). **Diagram Explanation:** The diagram presents a circle with the center labeled as \( J \). Points \( H \), \( L \), and \( K \) are marked on the circumference of the circle. The angle \( \angle HLK \) is indicated within the circle, intersecting the arc \( HK \). **Solution Steps:** To solve the problem, we can use the relationship between the central angle and the arc in a circle. Here are the steps: 1. The angle \( \angle HLK \) is given as \( 37^\circ \). 2. Note that \( \angle HLK \) is the inscribed angle that intercepts the minor arc \( HK \). 3. Recall the property of circles: the measure of an inscribed angle is half the measure of the intercepted arc. 4. Let \( m \) be the measure of the minor arc \( HK \). 5. According to the property: \( \angle HLK = \frac{1}{2} \times m \). 6. Substitute \( \angle HLK = 37^\circ \) into the equation: \( 37^\circ = \frac{1}{2} \times m \). 7. Solve for \( m \): \[ m = 2 \times 37^\circ \] \[ m = 74^\circ \] So, the measure of the minor arc \( HK \) is \( 74^\circ \).
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