3. In both the ammonia, NH3, synthesis and the production of SO3, according to ... N2(g) + 3 H2(g) 2 NH3(g) AH = - 92 kJ 2 SO2(g) + O2(g) 2 SO3(g) AH = - 180 kJ The mole fraction at equilibrium of the desired product (NH3, and SO3), is greater at lower temperatures. Yet, in the commercial production of these substances relatively high temperatures are used. Explain why this is so.
3. In both the ammonia, NH3, synthesis and the production of SO3, according to ... N2(g) + 3 H2(g) 2 NH3(g) AH = - 92 kJ 2 SO2(g) + O2(g) 2 SO3(g) AH = - 180 kJ The mole fraction at equilibrium of the desired product (NH3, and SO3), is greater at lower temperatures. Yet, in the commercial production of these substances relatively high temperatures are used. Explain why this is so.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:3. In both the ammonia, NH3, synthesis and the
production of SO3, according to
N2(g) + 3 H2(g) 2 NH3(g)
...
AH = - 92 kJ
2 SO2(g) + O2(g) 2 SO3(g) AH = - 180 kJ
The mole fraction at equilibrium of the
desired product (NH3, and SO3), is greater at
lower temperatures. Yet, in the commercial
production of these substances relatively high
temperatures are used. Explain why this is so.
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