3. In a recent poll of 900 randomly selected adults, 333 reported that they could not swim 24 yards (the length of a typical gymnasium lap pool). We want to construct a 95% confidence interval for the proportion of adults that cannot swim 24 yards. [Note: Assume the conditions required for this procedure have been satisfied.] a. Calculate the margin of error for the 95% confidence interval. Round to the nearest thousandth (third decimal place). b. Construct the 95% confidence interval for the proportion of adults who cannot swim 24 yards. Round to the nearest thousandth (third decimal place). c. A life guard claims that 30% of all adults cannot swim 24 yards. Does the confidence interval in part (c) support that claim? Explain.

3. In a recent poll of 900 randomly selected adults, 333 reported that they could not swim 24 yards (the length of a typical gymnasium lap pool). We want to construct a 95% confidence interval for the proportion of adults that cannot swim 24 yards. [Note: Assume the conditions required for this procedure have been satisfied.] a. Calculate the margin of error for the 95% confidence interval. Round to the nearest thousandth (third decimal place). b. Construct the 95% confidence interval for the proportion of adults who cannot swim 24 yards. Round to the nearest thousandth (third decimal place). c. A life guard claims that 30% of all adults cannot swim 24 yards. Does the confidence interval in part (c) support that claim? Explain.

Name: 3. In a recent poll of 900 randomly selected adults, 333 reported tha
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Description: 3. In a recent poll of 900 randomly selected adults, 333 reported that they could not swim 24yards (the length of a typical gymnasium lap pool). We want to construct a 95% confidenceinterval for the proportion of adults that cannot swim 24 yards. [N

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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