3. In a recent poll of 900 randomly selected adults, 333 reported that they could not swim 24 yards (the length of a typical gymnasium lap pool). We want to construct a 95% confidence interval for the proportion of adults that cannot swim 24 yards. [Note: Assume the conditions required for this procedure have been satisfied.] a. Calculate the margin of error for the 95% confidence interval. Round to the nearest thousandth (third decimal place). b. Construct the 95% confidence interval for the proportion of adults who cannot swim 24 yards. Round to the nearest thousandth (third decimal place). c. A life guard claims that 30% of all adults cannot swim 24 yards. Does the confidence interval in part (c) support that claim? Explain.
3. In a recent poll of 900 randomly selected adults, 333 reported that they could not swim 24 yards (the length of a typical gymnasium lap pool). We want to construct a 95% confidence interval for the proportion of adults that cannot swim 24 yards. [Note: Assume the conditions required for this procedure have been satisfied.] a. Calculate the margin of error for the 95% confidence interval. Round to the nearest thousandth (third decimal place). b. Construct the 95% confidence interval for the proportion of adults who cannot swim 24 yards. Round to the nearest thousandth (third decimal place). c. A life guard claims that 30% of all adults cannot swim 24 yards. Does the confidence interval in part (c) support that claim? Explain.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![3. In a recent poll of 900 randomly selected adults, 333 reported that they could not swim 24
yards (the length of a typical gymnasium lap pool). We want to construct a 95% confidence
interval for the proportion of adults that cannot swim 24 yards. [Note: Assume the conditions
required for this procedure have been satisfied.]
a. Calculate the margin of error for the 95% confidence interval. Round to the nearest
thousandth (third decimal place).
b. Construct the 95% confidence interval for the proportion of adults who cannot swim 24
yards. Round to the nearest thousandth (third decimal place).
c. A life guard claims that 30% of all adults cannot swim 24 yards. Does the confidence interval
in part (c) support that claim? Explain.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93b427c0-e1bb-413a-8e63-29bbe2e71a65%2Fe0bc6390-49e4-47ed-ab01-a4c3784aced6%2F47rfpb_processed.png&w=3840&q=75)
Transcribed Image Text:3. In a recent poll of 900 randomly selected adults, 333 reported that they could not swim 24
yards (the length of a typical gymnasium lap pool). We want to construct a 95% confidence
interval for the proportion of adults that cannot swim 24 yards. [Note: Assume the conditions
required for this procedure have been satisfied.]
a. Calculate the margin of error for the 95% confidence interval. Round to the nearest
thousandth (third decimal place).
b. Construct the 95% confidence interval for the proportion of adults who cannot swim 24
yards. Round to the nearest thousandth (third decimal place).
c. A life guard claims that 30% of all adults cannot swim 24 yards. Does the confidence interval
in part (c) support that claim? Explain.
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