3. If the specific gravity of the soil subjected to compaction is 2.70, a. Plot the compaction curve of the given data in the table below. 4.2 Water content (%) 5.1 7.8 Degree of Saturation, S (%) 28.9 60.1 b. Determine the maximum dry unit weight and optimum water content. 19.8 10.1 69.8 12.2 74.6
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- Laboratory compaction test results on a clayey soil are listed in the table below. Moisture content (%) Dry unit weight (kN/m³) 6 14.80 8 17.45 9 18.52 11 18.9 12 18.5 14 16.9 The following are the results of a field unit weight determination test on the same soil with the sand cone method: Calibrated dry density of Ottawa sand = 1,560 kg/m³ Calibrated mass of Ottawa sand to fill the cone = 0.565 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil from hole = 2.85 kg Moisture content of moist soil = 15.2% Determine: a. Dry unit weight of compaction in the field. (Enter your answer to three significant figures.) Ya = ]kN/m³ b. Relative compaction in the field. (Enter your answer to two significant figures.) R = |%Laboratory compaction test results for clayey silt are given in the following table. The soil G.-2.71. Water content% 6 8 9 12 Dry unit weight (kN/m²) 14.8 17.45 18.52 18.9 18.5 16.9 Plot the relation between water content and dry unit weight. Then, determine the maximum density and optimum moisture content.5. Following is the result of a modified proctor test. Determine the maximum dry unit weight, void ratio and saturation at optimum moisture content and energy of compaction. Make a tabulation of all your results. Volume of Mold (m³) Weight of Moise Soil in Mold (kN) OF Moisture Content 0.000945 10 0.000945 12 0.000945 14 0.000945 0.0177 16 0.000945 0.0173 18 0.000945 0.0166 20 COR
- The results from a soil compaction test are shown in the table below. The solid grains of the soil have a specific gravity of 2.65. Yary (kN m³) at 2.5% air voids Sample W. m/c(%) (KN/m') Yary (kN/m) 19 12 20.9 3. 16 20.2 4 20 19.7 Which series below gives the dry density at 2.5% air voids (samples 1 to 4) in above table: a. 20.5, 19.2, 17.8, 16.6 O b. 20.2, 19.2, 17.8, 17.0 O. 20.5, 19.2, 17.8, 17.0 O d. 20.5, 19.2, 18.1, 16.6Question 13 The compaction of a soil obtained from a standard compaction test is shown in the attached figure. At OMC (optimum moisture content) the degree of saturation = 93 %. What is the highest possible dry unit weight for this soil to have when the moisture content is 9 %? P (1+w) 20.0 1 10 Pa(s) 19.5 19.0 18.5 18.0 Dry unit weight, y, [kN/m³] 17.5 17.0 16.5 16.0 6 7 8 9 14. 1 10 11 12 13 14 Water content, w, [%] 15 16 G.P 1+ wG S 17 1813. A soil has a specific gravity of solids (Gs) of 2.65, a water content of 13% and a void ratio of 0.8. a. draw the phase diagram and fill it in with the numerical values b. determine the porosity, saturation, and the dry, saturated, and submerged unit weights in lb/ft³. using Gs= Ms me
- A proctor compaction test was conducted on a soil sample, and the following observations weremade:Water content, percent 7.7 11.5 14.6 17.5 19.7 21.2Mass of wet soil, g 1739 1919 2081 2033 1986 1948 1. determine the wet density in g/cm32. determine the dry density in g/cm33. determine the dry unit weight in kN/m34. construct the compaction curve 5. determine the optimum moisture content in percent 6. determine the maximum dry density in kN/m37. construct the 80% and 100% saturation lines using w% = 8, 12, 16, 20, and 24 8. calculate the saturation for the maximum dry density (ϒdmax in kN/m3) and the optimummoisture content (wopt %)Using Unified Soil Classification System, determine the type of soil, the coefficient of gradation and the group symbol. Passing No. 4 = 47 % Passing No. 200 = 22 % Di0 = 0.685 mm D30 = 1.391 mm De0 = 4.076 mm Plasticity for the minus No. 40 fraction: Liquid Limit = 35 % Plastic Limit = 23 %From the following data, solve for the degree of compaction. Field density test data: Weight of material taken from hole, kg. = Weight of sand to fill hole, kg. = Volume of hole, cu.m = 4.885 3.885 0.0028 Wet unit weight, kg/cu.m = Dry unit weight, kg/cu.m = 1745 1663 Laboratory Data: Maximum dry density, kg/cu.m. = 2250 Optimum Moisture Content, % = 8.10
- For a soil, given e= 0.75, w= 22%, Gs= 2.66, calculate the dry density of soil in slug/ft3. Note p of water= 1.94 slug/ft3 a. 2.85 b. 3.6 c. 2.95 d. 3.8Homework Chapter 3 31 Results from liquid and plastic limit tests conducted on soil are given below. No. of blows, N Moisture content (%) 14 38.4 16 36.5 20 33.1 28 27.0 If the plastic limit is PL = 13.4% a. Draw the flow curve and obtain the liquid limit. b. What is the plasticity index of the soil? Ans.: L.L = 29%, P.L = 15.6 3.2 Determine the liquidity index of the soil in Problem (1) if wWin situ = 32%. Ans.: L.I = 1.19% 3.3 Results from liquid and plastic limit tests conducted on soil are given below. No. of blows, N Moisture content (%) 13 18 27 22 If the plastic limit is PL = 19.1% a. Draw the flow curve and obtain the liquid limit. b. What is the plasticity index of the soil? Ans.: L.L = 23.6%, P.L = 4.5% 3.4 Determine the liquidity index of the soil in Problem (3) if win situ = 21% Ans.: L.I = 0.422% 3.5 A saturated soil used to determine the shrinkage limit has initial volume Vi = 20.2 cm3, final volume Vf = 14.3 cm3, the mass of wet soil M1 = 34 g, and mass of dry soil M2 =…Question 13 A saturated soil has the following characteristics Initial mass = 41.75 grams Final mass = 28 4 grams Initial Volume = 23 cm3 Final Volume = 15 cm3 Determine the specific gravity of soil solids. Round off to two decimal places. SUS