3. If a person rolls doubles when she tosses two dice, she wins $10. For the game to be fair, how much should she pay to play the game?
3. If a person rolls doubles when she tosses two dice, she wins $10. For the game to be fair, how much should she pay to play the game?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Question 3:** If a person rolls doubles when she tosses two dice, she wins $10. For the game to be fair, how much should she pay to play the game?
### Explanation:
In this problem, we need to determine the fair cost to play a game involving rolling two dice. The player wins $10 if she rolls doubles.
1. **Probability of Rolling Doubles:**
- There are 6 possible doubles when rolling two six-sided dice: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).
- The total number of outcomes when rolling two dice is \(6 \times 6 = 36\).
- Therefore, the probability of rolling doubles is \(\frac{6}{36} = \frac{1}{6}\).
2. **Expectation:**
- To find the fair cost, calculate the expected winnings of the game.
- Winning $10 has a probability of \(\frac{1}{6}\).
- Thus, the expected winnings are \(10 \times \frac{1}{6} = \frac{10}{6} = \frac{5}{3} \approx 1.67\).
3. **Fair Cost:**
- For the game to be fair, the cost to play should be equal to the expected winnings.
- Therefore, the fair cost is approximately $1.67.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff9d43275-adf6-4ed8-98f7-fff000442601%2F8d1f8e5d-ae08-433e-82aa-f1e80d2fb15a%2F2z0xbjl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 3:** If a person rolls doubles when she tosses two dice, she wins $10. For the game to be fair, how much should she pay to play the game?
### Explanation:
In this problem, we need to determine the fair cost to play a game involving rolling two dice. The player wins $10 if she rolls doubles.
1. **Probability of Rolling Doubles:**
- There are 6 possible doubles when rolling two six-sided dice: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).
- The total number of outcomes when rolling two dice is \(6 \times 6 = 36\).
- Therefore, the probability of rolling doubles is \(\frac{6}{36} = \frac{1}{6}\).
2. **Expectation:**
- To find the fair cost, calculate the expected winnings of the game.
- Winning $10 has a probability of \(\frac{1}{6}\).
- Thus, the expected winnings are \(10 \times \frac{1}{6} = \frac{10}{6} = \frac{5}{3} \approx 1.67\).
3. **Fair Cost:**
- For the game to be fair, the cost to play should be equal to the expected winnings.
- Therefore, the fair cost is approximately $1.67.
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