3. Identifying Extreme Values: Using the Normal Table in Reverse Steps: 1) Sketch the normal curve associated with the variable and locate the point that is of interest. 2) Use the standard normal table to obtain the z value corresponding to the point found in Step 1. 3) Obtain the x value having the z value found in Step 2. The following formula can be used to find the x value: x=z.0+H. 10=16 Example 6.4: Consider the IQ Scores in Example 6.2. 19505 94 95 Teacher took the average a. Find the 95th percentile of IQ scores. 100 X-00 16 「i695- そ100 X=1.645 x16 + 100= 126.3d b. Find the IQ score separating the bottom 10% from the top 90%. 5349 1003 -128=XーI00 T6 Example 6.5: A mandatory competency test for high school sonhomorer hog -1,28 79.52 with a mean of 400

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How do I turn a z value into an x value? 

The example in class was this: IQ scores are normally distributed with a mean of 100 and a standard deviation of 16. Find the 95th percentile. The answer was 126.32. 

I attached a picture of the example. 

I would really appreciate it if you could write an explanation for each step. 

,9495 Teacher took
3. Identifying Extreme Values: Using the Normal Table in Reverse
Steps:
1) Sketch the normal curve associated with the variable and locate the point that is of interest.
2) Use the standard normal table to obtain the z value corresponding to the point found in Step 1.
3) Obtain the x value having the z value found in Step 2. The following formula can be used to
M=D100
5%60=D16
find the x value: x=z.o+H.
Example 6.4: Consider the IQ Scores in Example 6.2.
a. Find the 95th percentile of IQ scores.
.100
9505
Teacher toolk
the average
X-100
16
li645= X-100
To
%3D
X= 1.645 x16 + l00 = 126.3
%3D
b. Find the IQ score separating the bottom 10% from the top 90%.
534 1003
-1.28=x-100
16
-1,28
x16+100%3D79.52
Example 6.5: A mandatory competency test for high school sophomores has a normal distribution
with a mean of 400 and a standard deviation of 100.
I den + c ot
Transcribed Image Text:,9495 Teacher took 3. Identifying Extreme Values: Using the Normal Table in Reverse Steps: 1) Sketch the normal curve associated with the variable and locate the point that is of interest. 2) Use the standard normal table to obtain the z value corresponding to the point found in Step 1. 3) Obtain the x value having the z value found in Step 2. The following formula can be used to M=D100 5%60=D16 find the x value: x=z.o+H. Example 6.4: Consider the IQ Scores in Example 6.2. a. Find the 95th percentile of IQ scores. .100 9505 Teacher toolk the average X-100 16 li645= X-100 To %3D X= 1.645 x16 + l00 = 126.3 %3D b. Find the IQ score separating the bottom 10% from the top 90%. 534 1003 -1.28=x-100 16 -1,28 x16+100%3D79.52 Example 6.5: A mandatory competency test for high school sophomores has a normal distribution with a mean of 400 and a standard deviation of 100. I den + c ot
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