**Preparing Solutions: An Educational Guide****Question 3: Preparing a 0.750 M Solution**Explore the methods to prepare 500.0 mL of a 0.750 M solution using the following substances:**a. Sulfuric acid from 18.0 M concentrated liquid**- To prepare a dilute solution from a concentrated solution, use the dilution formula: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) is the concentration of the concentrated solution (18.0 M) - \( V_1 \) is the volume of the concentrated solution required - \( C_2 \) is the desired concentration of the dilute solution (0.750 M) - \( V_2 \) is the final volume of the dilute solution (500.0 mL) Solve for \( V_1 \) to find out how much of the concentrated acid is needed.**b. Sodium carbonate powder**- Calculate the mass of sodium carbonate needed to make the solution using the formula: \[ \text{Moles} = \text{Molarity} \times \text{Volume} \] Then, multiply the moles by the molar mass of sodium carbonate to find the weight required.This educational resource aims to guide students in solution preparation by applying theoretical knowledge to practical scenarios.

a) Given: M1 = 18 M, M2 = 0.75 M, V2 = 500 mL, V1= ? Use dilution formula M1×V1=M2×V2 V1=M2×V2M1…

Answered: 3. How would you prepare 500.0 mL of a…

3. How would you prepare 500.0 mL of a 0.750 M solution using Sulfuric acid from 18.0 M concentrated liquid b. Sodium carbonate powder

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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