Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Preparing Solutions: An Educational Guide**
**Question 3: Preparing a 0.750 M Solution**
Explore the methods to prepare 500.0 mL of a 0.750 M solution using the following substances:
**a. Sulfuric acid from 18.0 M concentrated liquid**
- To prepare a dilute solution from a concentrated solution, use the dilution formula:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) is the concentration of the concentrated solution (18.0 M)
- \( V_1 \) is the volume of the concentrated solution required
- \( C_2 \) is the desired concentration of the dilute solution (0.750 M)
- \( V_2 \) is the final volume of the dilute solution (500.0 mL)
Solve for \( V_1 \) to find out how much of the concentrated acid is needed.
**b. Sodium carbonate powder**
- Calculate the mass of sodium carbonate needed to make the solution using the formula:
\[ \text{Moles} = \text{Molarity} \times \text{Volume} \]
Then, multiply the moles by the molar mass of sodium carbonate to find the weight required.
This educational resource aims to guide students in solution preparation by applying theoretical knowledge to practical scenarios.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbac5240b-2cb0-46ee-b04c-8db0831d9625%2Fca143a25-12ec-49f3-a623-5e47a426042e%2Fg0rqbsp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Preparing Solutions: An Educational Guide**
**Question 3: Preparing a 0.750 M Solution**
Explore the methods to prepare 500.0 mL of a 0.750 M solution using the following substances:
**a. Sulfuric acid from 18.0 M concentrated liquid**
- To prepare a dilute solution from a concentrated solution, use the dilution formula:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) is the concentration of the concentrated solution (18.0 M)
- \( V_1 \) is the volume of the concentrated solution required
- \( C_2 \) is the desired concentration of the dilute solution (0.750 M)
- \( V_2 \) is the final volume of the dilute solution (500.0 mL)
Solve for \( V_1 \) to find out how much of the concentrated acid is needed.
**b. Sodium carbonate powder**
- Calculate the mass of sodium carbonate needed to make the solution using the formula:
\[ \text{Moles} = \text{Molarity} \times \text{Volume} \]
Then, multiply the moles by the molar mass of sodium carbonate to find the weight required.
This educational resource aims to guide students in solution preparation by applying theoretical knowledge to practical scenarios.
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