3. How many mL of 0.1421N KOH are required to neutralize 13.72 mL of 0.06850 M H2SO4? 4. Given the ff data: 1.00 mL≎ 1.117 mL HCl, the HCl is 0.4876 N. How much water should be added to 100 mL of the alkali to make it 0.500 N? 5. A solution of H2SO4 is found to be 0.5172 N and 39.65 mL of it are equivalent to 21.74 mL of standard alkali solution. What is the N of the alkali and how many grams of sulfamic acid (HSO3.NH2) will 1.00 mL of it neutralize? 6. In standardizing a solution of NaOH against 1.431g of KHC8H4O4, the analyst uses 35.50 mL of the alkali and has to run back with 5.12 mL of acid ( 1mL ≎0.0031g Na2O) What is the normality of NaOH? 7. A solution of H2SO4 is standardized against a sample of which has been previously found to contain 92.44% CaCO3 and no other basic material. The sample weighing 0.7423 g is treated with 42.42 mL of the acid and the excess acid then requires 11.22 mL of NaOH solution. If 1.00 mL of the acid is equivalent to 0.9976 mL of the NaOH, what is the N of each solution? 8. - If 44.97 mL of a solution of HCl are equivalent to 43.76 mL of a solution of NaOH, and if 49.14 mL of the latter will neutralize 0.2162 g of KHC2O4.H2C2O4.2H2O, what volume of water should be added to 100 mL of the HCl in order to prepare a mixture which is 0.0500 N as an acid? 9. What is the equivalent weight of an organic acid if 44.00 mL NaOH solution (1.000 mL ≎ 1.100 mL HCl ≎ 0.01001 g CaCO3) are required to neutralize 0.5192 g of the organic acid?
3. How many mL of 0.1421N KOH are required to neutralize 13.72 mL of 0.06850 M H2SO4?
4. Given the ff data: 1.00 mL≎ 1.117 mL HCl, the HCl is 0.4876 N. How much water should be added to 100 mL of the alkali to make it 0.500 N?
5. A solution of H2SO4 is found to be 0.5172 N and 39.65 mL of it are equivalent to 21.74 mL of standard alkali solution. What is the N of the alkali and how many grams of sulfamic acid (HSO3.NH2) will 1.00 mL of it neutralize?
6. In standardizing a solution of NaOH against 1.431g of KHC8H4O4, the analyst uses 35.50 mL of the alkali and has to run back with 5.12 mL of acid ( 1mL ≎0.0031g Na2O) What is the normality of NaOH?
7. A solution of H2SO4 is standardized against a sample of which has been previously found to contain 92.44% CaCO3 and no other basic material. The sample weighing 0.7423 g is treated with 42.42 mL of the acid and the excess acid then requires 11.22 mL of NaOH solution. If 1.00 mL of the acid is equivalent to 0.9976 mL of the NaOH, what is the N of each solution?
8. - If 44.97 mL of a solution of HCl are equivalent to 43.76 mL of a solution of NaOH, and if 49.14 mL of the latter will neutralize 0.2162 g of KHC2O4.H2C2O4.2H2O, what volume of water should be added to 100 mL of the HCl in order to prepare a mixture which is 0.0500 N as an acid?
9. What is the equivalent weight of an organic acid if 44.00 mL NaOH solution (1.000 mL ≎ 1.100 mL HCl ≎ 0.01001 g CaCO3) are required to neutralize 0.5192 g of the organic acid?
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