3. How can you make 450mL 1.8M NaOH solution out of a) solid NaOH b) 6 M NAOH c) 0.3M NAOH

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Chapter1: Chemical Foundations
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**Question:**

How can you make 450 mL of a 1.8 M NaOH solution using:

a) Solid NaOH  
b) 6 M NaOH  
c) 0.3 M NaOH  

**Explanation:**

1. **Using Solid NaOH (Option a):**
   - To prepare the solution from solid NaOH, you would need to calculate the amount of NaOH required by using the formula:
     \[
     \text{Moles of NaOH} = \text{Molarity} \times \text{Volume in liters}
     \]
   - Convert 450 mL to liters and use the molar mass of NaOH to find the mass needed.

2. **Using 6 M NaOH (Option b):**
   - Use dilution formula:
     \[
     M_1V_1 = M_2V_2
     \]
   - Where \( M_1 \) and \( V_1 \) are the molarity and volume of the 6 M solution, and \( M_2 \) and \( V_2 \) are the molarity and desired volume (1.8 M and 450 mL).

3. **Using 0.3 M NaOH (Option c):**
   - Again, use the dilution formula, solving for the volume of 0.3 M NaOH needed to achieve the desired 450 mL of 1.8 M solution.

This exercise encourages understanding of molarity calculations, the use of dilution formula, and the basic laboratory procedure for preparing solutions.
Transcribed Image Text:**Question:** How can you make 450 mL of a 1.8 M NaOH solution using: a) Solid NaOH b) 6 M NaOH c) 0.3 M NaOH **Explanation:** 1. **Using Solid NaOH (Option a):** - To prepare the solution from solid NaOH, you would need to calculate the amount of NaOH required by using the formula: \[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume in liters} \] - Convert 450 mL to liters and use the molar mass of NaOH to find the mass needed. 2. **Using 6 M NaOH (Option b):** - Use dilution formula: \[ M_1V_1 = M_2V_2 \] - Where \( M_1 \) and \( V_1 \) are the molarity and volume of the 6 M solution, and \( M_2 \) and \( V_2 \) are the molarity and desired volume (1.8 M and 450 mL). 3. **Using 0.3 M NaOH (Option c):** - Again, use the dilution formula, solving for the volume of 0.3 M NaOH needed to achieve the desired 450 mL of 1.8 M solution. This exercise encourages understanding of molarity calculations, the use of dilution formula, and the basic laboratory procedure for preparing solutions.
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