3. Given the network: RG125.0.0.0 /8EMU KA 223800A XROWT a. What is the original subnet mask for this network? b. How many bits are in the host field for this network? 255.0.0.0 24 as CentIf we want to set up 1000 subnets, how many host bits must be used for subnetting? lendue aint ni 1 20 total subnets 10
3. Given the network: RG125.0.0.0 /8EMU KA 223800A XROWT a. What is the original subnet mask for this network? b. How many bits are in the host field for this network? 255.0.0.0 24 as CentIf we want to set up 1000 subnets, how many host bits must be used for subnetting? lendue aint ni 1 20 total subnets 10
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
May you check my work? Is it correct?
![3.
Given the network: 125.0.0.0 /88MM 22300 XROWT2
ab What is the original subnet mask for this network?
Tendul
b. How many bits are in the host field for this network?
255.0.0.0
24
20 C. If we want to set up 1000 subnets, how many host bits must be used for subnetting?
tendue aint ni
d. How many subnets can we create from this?
tendua aidt ni
1024
1010
What final prefix length will be used for this subnet design?
/18
What final subnet mask will be used for this subnet design? 255.255. 192.0
14
9.
How many bits are left over that can be used for host addresses?
h. How many IP addresses would be created on each subnet?
16382 assignable host addresses
acar
16384 total IP addresses
Complete the following table for the first 5 subnets in this network. Give the subnet number (starting from 0).
subnet address, first host address, last host address and, subnet (directed) broadcast address.
e.
f.
i.
Subnet
Number
0
3
4
j.
Subnet
Number
Subnet & Host Bits
2nd & 3rd octets (in binary)
101g
1020
1021
1022
1023
00000000
00000000
00000000
01000000
8800888..
do000 000
11000000
00000001
00000000
Subnet & Host Bits
2nd & 3rd octets (in binary)
UIIIICTO
11600000
Divo
10000000
Complete the following table for the last 5 subnets in this network. Give the subnet number, subnet address,
host address range, subnet (directed) broadcast address.
HIISHO
01000000
MILIO
00000000
||||||||
00000000
total subnets
Last Host
Subnet Address
(4 bytes)
Subnet (Directed)
Broadcast Address
First Host
(last 3 bytes)
(last 3 bytes)
(last 3 bytes)
125.0.0.1 12.5.0.63.25 125.0.63.255
125.0.0.0
125.0.64.0 125.0.64.125.0.127.254 125.0.127.255
125.0.128.0 125.0.128,1 125.0.191.254 125.0.191.255
125.0.192.0 125.0.192,1125.0.255.254 125.0.255.255
125.1.0.1125.1.63.254 125.1.63.255
125.1.0.0
Subnet Address
(4 bytes)
10
en 001 001.001.02
11.6.7 W02_SUBNETTING-2 (ASSIGNED).DOCX
est ser ses 881 887
First Host
(last 3 bytes)
254
Subnet (Directed)
Last Host
Broadcast Address
(last 3 bytes)
(last 3 bytes)
125.254.192.0125,254.192 125.254.265 125.254.255.255
125.254.128.0 125.254.128.1125.254.191. 125.254.191.255
125,254.64.0 125.264.64.125.254.127 125.254.127.255
125.254.0.0
254
125.254.0.125.254.63.125.254.63.255
254
125.255.0.0 125.255.0.125.256,63.125.255.63.255
254
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Transcribed Image Text:3.
Given the network: 125.0.0.0 /88MM 22300 XROWT2
ab What is the original subnet mask for this network?
Tendul
b. How many bits are in the host field for this network?
255.0.0.0
24
20 C. If we want to set up 1000 subnets, how many host bits must be used for subnetting?
tendue aint ni
d. How many subnets can we create from this?
tendua aidt ni
1024
1010
What final prefix length will be used for this subnet design?
/18
What final subnet mask will be used for this subnet design? 255.255. 192.0
14
9.
How many bits are left over that can be used for host addresses?
h. How many IP addresses would be created on each subnet?
16382 assignable host addresses
acar
16384 total IP addresses
Complete the following table for the first 5 subnets in this network. Give the subnet number (starting from 0).
subnet address, first host address, last host address and, subnet (directed) broadcast address.
e.
f.
i.
Subnet
Number
0
3
4
j.
Subnet
Number
Subnet & Host Bits
2nd & 3rd octets (in binary)
101g
1020
1021
1022
1023
00000000
00000000
00000000
01000000
8800888..
do000 000
11000000
00000001
00000000
Subnet & Host Bits
2nd & 3rd octets (in binary)
UIIIICTO
11600000
Divo
10000000
Complete the following table for the last 5 subnets in this network. Give the subnet number, subnet address,
host address range, subnet (directed) broadcast address.
HIISHO
01000000
MILIO
00000000
||||||||
00000000
total subnets
Last Host
Subnet Address
(4 bytes)
Subnet (Directed)
Broadcast Address
First Host
(last 3 bytes)
(last 3 bytes)
(last 3 bytes)
125.0.0.1 12.5.0.63.25 125.0.63.255
125.0.0.0
125.0.64.0 125.0.64.125.0.127.254 125.0.127.255
125.0.128.0 125.0.128,1 125.0.191.254 125.0.191.255
125.0.192.0 125.0.192,1125.0.255.254 125.0.255.255
125.1.0.1125.1.63.254 125.1.63.255
125.1.0.0
Subnet Address
(4 bytes)
10
en 001 001.001.02
11.6.7 W02_SUBNETTING-2 (ASSIGNED).DOCX
est ser ses 881 887
First Host
(last 3 bytes)
254
Subnet (Directed)
Last Host
Broadcast Address
(last 3 bytes)
(last 3 bytes)
125.254.192.0125,254.192 125.254.265 125.254.255.255
125.254.128.0 125.254.128.1125.254.191. 125.254.191.255
125,254.64.0 125.264.64.125.254.127 125.254.127.255
125.254.0.0
254
125.254.0.125.254.63.125.254.63.255
254
125.255.0.0 125.255.0.125.256,63.125.255.63.255
254
HONOLULU COMMUNITY COLLEGE) SOMFETIME OW3 OF 41
Expert Solution
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Step 1: Introduction
As per our company guidelines only 3 sub parts will be answered. So, please repost the remaining questions separately.
All answers provided in the sheet are correct but i am providing explanation for first 3 questions only.
Subnetting is a process of dividng a single physical network into small logical sub networks which are called as subnets. It reduces the network traffic and also decreases the complexity of network.
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