3. Given the following elements of a typical compound curve: Angle of intersection (11) = 21°20' Angle of intersection (12) = 30°02¹ Degree of 1 curve (D1) = 4°30' Degree of 2nd curve (D2) = 5°01' Stationing of Point of Intersection on 1st curve, A= 10+112
3. Given the following elements of a typical compound curve: Angle of intersection (11) = 21°20' Angle of intersection (12) = 30°02¹ Degree of 1 curve (D1) = 4°30' Degree of 2nd curve (D2) = 5°01' Stationing of Point of Intersection on 1st curve, A= 10+112
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![3.Given the following elements of a typical compound curve:
Angle of intersection (11) = 21°20'
Angle of intersection (12) = 30°02'
Degree of 1 curve (D1) = 4°30'
Degree of 2nd curve (D2) = 5°01'
Stationing of Point of Intersection on 1st curve, A = 10+112
If a highway engineer desires to change this compound curve with a simple curve such that PT
will be in the same position, as well as the direction of the tangents, find the following:
a. Degree of the simple curve.
b. Stationing of the Point of Tangency (PT)
c. Area of fillet, in sqm.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fdacf83-4e41-472e-a742-4af5bc7df5a7%2Fb75b24be-7efa-4e92-827d-24b266ede4b9%2Fbptiiu6_processed.png&w=3840&q=75)
Transcribed Image Text:3.Given the following elements of a typical compound curve:
Angle of intersection (11) = 21°20'
Angle of intersection (12) = 30°02'
Degree of 1 curve (D1) = 4°30'
Degree of 2nd curve (D2) = 5°01'
Stationing of Point of Intersection on 1st curve, A = 10+112
If a highway engineer desires to change this compound curve with a simple curve such that PT
will be in the same position, as well as the direction of the tangents, find the following:
a. Degree of the simple curve.
b. Stationing of the Point of Tangency (PT)
c. Area of fillet, in sqm.
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