3. Given the diagram below, prove DC = BC A 1. 4. 6. D E AD=AB 2. ZDEA is a right angle 3. ZDEA + ZBEA = 180° ZBEA = 180° - ZDEA ZBEA = 180°-90° ZBEA = 90° 5. ABEA is a right triangle. B Statement 10. ADEA is a right triangle. AE = AE 7. AAED=AAEB 8. DE=BE 9-EC-EC ZDEC = ZAEB ZDEA=ZCEB 11. DEC is a right angle. 1. 2. 3. 4. 5. 6. 7. 8. CPCTC. 9. 10. C Reason
3. Given the diagram below, prove DC = BC A 1. 4. 6. D E AD=AB 2. ZDEA is a right angle 3. ZDEA + ZBEA = 180° ZBEA = 180° - ZDEA ZBEA = 180°-90° ZBEA = 90° 5. ABEA is a right triangle. B Statement 10. ADEA is a right triangle. AE = AE 7. AAED=AAEB 8. DE=BE 9-EC-EC ZDEC = ZAEB ZDEA=ZCEB 11. DEC is a right angle. 1. 2. 3. 4. 5. 6. 7. 8. CPCTC. 9. 10. C Reason
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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