3. Given a prime number k, we define Q(√k) = {a+b√k : a, b ≤ Q} ≤ R. This set becomes a field when equipped with the usual addition and multiplication operations inherited from R. (a) For each non-zero x € Q(√2) of the form x = a +b√√2, prove that x-¹ b = a²-26² a²-26² √2. (b) Show that √√2 Q(√3). You can use, without proof, the fact that √2, √3, are all irrational numbers. (c) Show that there cannot be a function : Q(√2)→ Q(√3) so that 6: (Q(√2) - {0}, ×) → (Q(√3) − {0}, ×) and 6: (Q(√2), +) → (Q(√3), +) are both group isomorphisms. Hint: What can you say about $(√2 × √√2)?
3. Given a prime number k, we define Q(√k) = {a+b√k : a, b ≤ Q} ≤ R. This set becomes a field when equipped with the usual addition and multiplication operations inherited from R. (a) For each non-zero x € Q(√2) of the form x = a +b√√2, prove that x-¹ b = a²-26² a²-26² √2. (b) Show that √√2 Q(√3). You can use, without proof, the fact that √2, √3, are all irrational numbers. (c) Show that there cannot be a function : Q(√2)→ Q(√3) so that 6: (Q(√2) - {0}, ×) → (Q(√3) − {0}, ×) and 6: (Q(√2), +) → (Q(√3), +) are both group isomorphisms. Hint: What can you say about $(√2 × √√2)?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![3.
Given a prime number k, we define Q(√k) = {a+b√k : a,b ≤ Q} ≤ R. This set
becomes a field when equipped with the usual addition and multiplication operations inherited
from R.
(a) For each non-zero x = Q(√2) of the form x = a +b√√/2, prove that x-¹
a
=
a²26²
b
a²-26²
√2.
(b) Show that √2 Q(√3). You can use, without proof, the fact that √2,√√3,
are all
irrational numbers.
(c) Show that there cannot be a function : Q(√2)→ Q(√3) so that
6: (Q(√2) - {0}, ×) → (Q(√3) − {0}, ×)
and
6: (Q(√2), +) → (Q(√3), +)
are both group isomorphisms. Hint: What can you say about (√2 × √√2)?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe0beb8cb-6210-47c6-a15d-53a21e6e76e5%2F87682e9f-aec2-424c-afdb-c1fedbefb9e8%2Ffh2qzd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.
Given a prime number k, we define Q(√k) = {a+b√k : a,b ≤ Q} ≤ R. This set
becomes a field when equipped with the usual addition and multiplication operations inherited
from R.
(a) For each non-zero x = Q(√2) of the form x = a +b√√/2, prove that x-¹
a
=
a²26²
b
a²-26²
√2.
(b) Show that √2 Q(√3). You can use, without proof, the fact that √2,√√3,
are all
irrational numbers.
(c) Show that there cannot be a function : Q(√2)→ Q(√3) so that
6: (Q(√2) - {0}, ×) → (Q(√3) − {0}, ×)
and
6: (Q(√2), +) → (Q(√3), +)
are both group isomorphisms. Hint: What can you say about (√2 × √√2)?
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