3. Give the complete electron flow of the S1 reaction, be sure to clearly show the electrons that are flowing. Br CH,CH,CH,CH,ÓH, Bī CH-CH-CH-CH-OH

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Chapter1: Chemical Foundations
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**Chapter 6, 7: Understanding Reaction Mechanisms**

1. **S<sub>N</sub>2 Reaction:**
   - **Reactants:** An alkoxide ion (OK⁻) and a bromoalkane.
   - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol).
   - **Products:** Ether and potassium bromide (KBr).
   - **Description:** An S<sub>N</sub>2 reaction involves a single-step nucleophilic substitution where the nucleophile (OK⁻) directly attacks the carbon atom bonded to the leaving group (Br), displacing it. Electrons flow from the nucleophile to the carbon atom.

2. **E2 Reaction:**
   - **Reactants:** An alkoxide ion (OK⁻) and a bromoalkane.
   - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol).
   - **Products:** Alkene, water, and potassium bromide (KBr).
   - **Description:** An E2 reaction is a bimolecular elimination where the base (OK⁻) removes a hydrogen atom from the carbon adjacent to the one bonded to the leaving group (Br). This results in the formation of a double bond (alkene) and the release of Br⁻ as a leaving group.

3. **S<sub>N</sub>1 Reaction:**
   - **Reactants:** Tertiary bromoalkane.
   - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol).
   - **Products:** Ether and a secondary carbocation intermolecular complex with bromide.
   - **Description:** An S<sub>N</sub>1 reaction involves a two-step mechanism where the leaving group (Br⁻) first dissociates, forming a carbocation intermediate. This carbocation is then attacked by the solvent (CH₃CH₂CH₂CH₂OH), leading to ether formation.

4. **E1 Reaction:**
   - **Reactants:** Tertiary bromoalkane.
   - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol).
   - **Products:** Alkene, a protonated alcohol (CH₃CH₂CH₂CH₂OH₂⁺), and bromide ion (Br⁻).
   - **Description:** An E1 reaction involves a two
Transcribed Image Text:**Chapter 6, 7: Understanding Reaction Mechanisms** 1. **S<sub>N</sub>2 Reaction:** - **Reactants:** An alkoxide ion (OK⁻) and a bromoalkane. - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol). - **Products:** Ether and potassium bromide (KBr). - **Description:** An S<sub>N</sub>2 reaction involves a single-step nucleophilic substitution where the nucleophile (OK⁻) directly attacks the carbon atom bonded to the leaving group (Br), displacing it. Electrons flow from the nucleophile to the carbon atom. 2. **E2 Reaction:** - **Reactants:** An alkoxide ion (OK⁻) and a bromoalkane. - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol). - **Products:** Alkene, water, and potassium bromide (KBr). - **Description:** An E2 reaction is a bimolecular elimination where the base (OK⁻) removes a hydrogen atom from the carbon adjacent to the one bonded to the leaving group (Br). This results in the formation of a double bond (alkene) and the release of Br⁻ as a leaving group. 3. **S<sub>N</sub>1 Reaction:** - **Reactants:** Tertiary bromoalkane. - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol). - **Products:** Ether and a secondary carbocation intermolecular complex with bromide. - **Description:** An S<sub>N</sub>1 reaction involves a two-step mechanism where the leaving group (Br⁻) first dissociates, forming a carbocation intermediate. This carbocation is then attacked by the solvent (CH₃CH₂CH₂CH₂OH), leading to ether formation. 4. **E1 Reaction:** - **Reactants:** Tertiary bromoalkane. - **Solvent:** CH₃CH₂CH₂CH₂OH (butanol). - **Products:** Alkene, a protonated alcohol (CH₃CH₂CH₂CH₂OH₂⁺), and bromide ion (Br⁻). - **Description:** An E1 reaction involves a two
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