3. For the reaction below, there is 100 g of each reactant available. Which reagent is the limiting reagent? [Molar Mass in g/mol: MnO, 86.9; KOH = 56.1; O, = 32.0; CI, = 70.9] 2 MnO, + 4 KOH + O, + CI -2 KMNO, + 2KCI + 2 H,0 %3D %3D %3D %3D
3. For the reaction below, there is 100 g of each reactant available. Which reagent is the limiting reagent? [Molar Mass in g/mol: MnO, 86.9; KOH = 56.1; O, = 32.0; CI, = 70.9] 2 MnO, + 4 KOH + O, + CI -2 KMNO, + 2KCI + 2 H,0 %3D %3D %3D %3D
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How do you solve question number 3? What reagent is the limiting reagent?
![The balanced equation shows that 1.00 mol of NH, reacts with 1 mole(s) of O,
2. Calculate the mass of hydrogen formed when 27g of aluminum reacts with excess
hydrochloric acid according to the balanced equation below.
2 Al + 6 HCI 2 AICI, + 3 H2
19A1Km mol H2 3g H2
3. For the reaction below, there is 100 g of each reactant available. Which reagent is the
limiting reagent? [Molar Mass in g/mol: MnO, 86.9; KOH = 56.1; O, = 32.0; Cl, = 70.9]
2 MnO, + 4 KOH + O, + CI 2 KMNO + 2KCI + 2 H,0
4. The reaction of 7.8 g benzene, C,Hg, with excess HNO, resulted in 0.90 g of H,O. W
is the percent yield?
(Molar Mass (g/mol): C,H, = 78; HN0, = 63; C,H,NO, = 123; H,0 = 18]
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Transcribed Image Text:The balanced equation shows that 1.00 mol of NH, reacts with 1 mole(s) of O,
2. Calculate the mass of hydrogen formed when 27g of aluminum reacts with excess
hydrochloric acid according to the balanced equation below.
2 Al + 6 HCI 2 AICI, + 3 H2
19A1Km mol H2 3g H2
3. For the reaction below, there is 100 g of each reactant available. Which reagent is the
limiting reagent? [Molar Mass in g/mol: MnO, 86.9; KOH = 56.1; O, = 32.0; Cl, = 70.9]
2 MnO, + 4 KOH + O, + CI 2 KMNO + 2KCI + 2 H,0
4. The reaction of 7.8 g benzene, C,Hg, with excess HNO, resulted in 0.90 g of H,O. W
is the percent yield?
(Molar Mass (g/mol): C,H, = 78; HN0, = 63; C,H,NO, = 123; H,0 = 18]
%3D
%3D
%3D
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