3.) For the following compounds, write below whether the protons pointed to are enantiotopic, homotopic, or diastereotopic. Please include the number of signals the particular protons would represent in a 'H-NMR spectrum. OH HH нн С

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### Topic: Identifying Enantiotopic, Homotopic, or Diastereotopic Protons in Compounds

#### Introduction:
In this exercise, we will classify specific protons in given molecular structures as enantiotopic, homotopic, or diastereotopic. Additionally, we'll determine the number of signals these protons would represent in a ^1H-NMR spectrum.

#### Problem Statement:
3. For the following compounds, identify whether the protons pointed to are enantiotopic, homotopic, or diastereotopic. Please include the number of signals the particular protons would represent in a ^1H-NMR spectrum.

#### Molecular Structures:
Three different molecular structures are presented, each with arrows pointing to particular protons:

1. **First Compound: Benzyl Alcohol Derivative**
   - Structure: A benzene ring attached to a carbon chain where the carbon chain includes:
     - A CH group (with protons indicated by an arrow).

2. **Second Compound: Symmetrical Disubstituted Benzene**
   - Structure: A benzene ring attached to a carbon chain where the carbon chain includes:
     - Two equivalent CH groups (with protons indicated by arrows).

3. **Third Compound: Monochlorobenzene Derivative**
   - Structure: A benzene ring with a chlorine substituent, attached to a carbon chain where the carbon chain includes:
     - A carbon with two hydrogen atoms (with protons indicated by arrows).

#### Explanation:
For each of these compounds, we'll evaluate the indicated protons:

1. **First Compound:**
   - The two protons on the CH group of the benzyl alcohol derivative can be either enantiotopic or diastereotopic depending on their environment and symmetry.
   
2. **Second Compound:**
   - The indicated protons on the symmetrical disubstituted benzene span equivalent positions (homotopic) that will result in a single NMR signal.
   
3. **Third Compound:**
   - The protons in the monochlorobenzene derivative are enantiotopic if placing a different group on the carbon would result in non-superimposable mirror images. They contribute multiple signals in the ^1H-NMR spectrum if they are in a non-equivalent magnetic environment.

#### Conclusion:
By examining each structure in detail and placing distinguishing groups, one can identify the environments as enantiotopic, homot
Transcribed Image Text:### Topic: Identifying Enantiotopic, Homotopic, or Diastereotopic Protons in Compounds #### Introduction: In this exercise, we will classify specific protons in given molecular structures as enantiotopic, homotopic, or diastereotopic. Additionally, we'll determine the number of signals these protons would represent in a ^1H-NMR spectrum. #### Problem Statement: 3. For the following compounds, identify whether the protons pointed to are enantiotopic, homotopic, or diastereotopic. Please include the number of signals the particular protons would represent in a ^1H-NMR spectrum. #### Molecular Structures: Three different molecular structures are presented, each with arrows pointing to particular protons: 1. **First Compound: Benzyl Alcohol Derivative** - Structure: A benzene ring attached to a carbon chain where the carbon chain includes: - A CH group (with protons indicated by an arrow). 2. **Second Compound: Symmetrical Disubstituted Benzene** - Structure: A benzene ring attached to a carbon chain where the carbon chain includes: - Two equivalent CH groups (with protons indicated by arrows). 3. **Third Compound: Monochlorobenzene Derivative** - Structure: A benzene ring with a chlorine substituent, attached to a carbon chain where the carbon chain includes: - A carbon with two hydrogen atoms (with protons indicated by arrows). #### Explanation: For each of these compounds, we'll evaluate the indicated protons: 1. **First Compound:** - The two protons on the CH group of the benzyl alcohol derivative can be either enantiotopic or diastereotopic depending on their environment and symmetry. 2. **Second Compound:** - The indicated protons on the symmetrical disubstituted benzene span equivalent positions (homotopic) that will result in a single NMR signal. 3. **Third Compound:** - The protons in the monochlorobenzene derivative are enantiotopic if placing a different group on the carbon would result in non-superimposable mirror images. They contribute multiple signals in the ^1H-NMR spectrum if they are in a non-equivalent magnetic environment. #### Conclusion: By examining each structure in detail and placing distinguishing groups, one can identify the environments as enantiotopic, homot
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