Need help with question 3 a, b (S) + 3 02 (g)2. This reaction has an equilibrium constant of K, = 2.2 x 106 at 298K.2 COF, (g) → CO, (g) + CF, (g)Calculate K, for each rection and predict whether reactants or products will be favored at equilibrium.a. COF, (g) →(6) *1) + (6) F09 -b. 6 COF2 (g) → 3 CO2 (g) + 3 CF, (g)c. 2 CO2 (g) + 2 CF, (g) → 4 COF, (g)3. For the following calculate either K, if Ke is given or calculate Ke if Kp is given. Use a temperature of 900. K.a. I2 (g) → 2I (g) K, = 6.26 * 10-22b. N2 (g) + 3 H2 (g) → 2 NHạ (g) K. = 3.7 * 10®

As you have asked subparts (a) and (b) of question 3, we will solve the same for you. 3 (a) I2 (g)…

3. For the following calculate either K, if Ke is given or calculate Ke if Kp is given. Use a temperature of 900. K. a. I2 (g) → 2 I (g) K, = 6.26 10-22 b. N2 (g) + 3 H2 (g) → 2 NH3 (g) K. = 3.7 10®

3. For the following calculate either K, if Ke is given or calculate Ke if Kp is given. Use a temperature of 900. K. a. I2 (g) → 2 I (g) K, = 6.26 10-22 b. N2 (g) + 3 H2 (g) → 2 NH3 (g) K. = 3.7 10®

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 56QRT

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Concept explainers

Ionic Equilibrium

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Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Question

Need help with question 3 a, b

(S) + 3 02 (g)
2. This reaction has an equilibrium constant of K, = 2.2 x 106 at 298K.
2 COF, (g) → CO, (g) + CF, (g)
Calculate K, for each rection and predict whether reactants or products will be favored at equilibrium.
a. COF, (g) →
(6) *1) + (6) F09 -
b. 6 COF2 (g) → 3 CO2 (g) + 3 CF, (g)
c. 2 CO2 (g) + 2 CF, (g) → 4 COF, (g)
3. For the following calculate either K, if Ke is given or calculate Ke if Kp is given. Use a temperature of 900. K.
a. I2 (g) → 2I (g) K, = 6.26 * 10-22
b. N2 (g) + 3 H2 (g) → 2 NHạ (g) K. = 3.7 * 10®

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