3. For each problem, find the general solution to x' = Ax, where A is the given matrix. (a) A = -4 (b) A =

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### Linear Algebra: General Solutions to Differential Equations

In this exercise, we aim to find the general solution to the differential equation given by \( x' = Ax \) where \( A \) is the provided matrix.

---

#### Problem Statement:

For each problem, find the general solution to \( x' = Ax \), where \( A \) is the given matrix.

---

#### (a) 
\[ A = \begin{pmatrix} 2 & 0 \\ -4 & -2 \end{pmatrix} \]

---

#### (b)
\[ A = \begin{pmatrix}
-4 & -8 \\
4 & 4
\end{pmatrix} \]

---

### Explanation:

To determine the general solution for the differential equation \( x' = Ax \):

1. **Find the Eigenvalues**: Solve \(\det(A - \lambda I) = 0\) to find the eigenvalues \(\lambda\).
  
2. **Find the Eigenvectors**: For each eigenvalue \(\lambda\), solve \((A - \lambda I)\mathbf{v} = 0\) to find the eigenvectors \(\mathbf{v}\).

3. **Construct the General Solution**: General solution will be of the form \(x(t) = c_1 e^{\lambda_1 t} \mathbf{v}_1 + c_2 e^{\lambda_2 t} \mathbf{v}_2\), where \(\lambda_1, \lambda_2\) and \(\mathbf{v}_1, \mathbf{v}_2\) are the eigenvalues and corresponding eigenvectors, and \(c_1, c_2\) are arbitrary constants.

---

Utilize this procedure to find the solutions for the matrices provided in problems (a) and (b). If additional support or graphical descriptions are necessary, consult supplementary learning materials or a tutor.
Transcribed Image Text:--- ### Linear Algebra: General Solutions to Differential Equations In this exercise, we aim to find the general solution to the differential equation given by \( x' = Ax \) where \( A \) is the provided matrix. --- #### Problem Statement: For each problem, find the general solution to \( x' = Ax \), where \( A \) is the given matrix. --- #### (a) \[ A = \begin{pmatrix} 2 & 0 \\ -4 & -2 \end{pmatrix} \] --- #### (b) \[ A = \begin{pmatrix} -4 & -8 \\ 4 & 4 \end{pmatrix} \] --- ### Explanation: To determine the general solution for the differential equation \( x' = Ax \): 1. **Find the Eigenvalues**: Solve \(\det(A - \lambda I) = 0\) to find the eigenvalues \(\lambda\). 2. **Find the Eigenvectors**: For each eigenvalue \(\lambda\), solve \((A - \lambda I)\mathbf{v} = 0\) to find the eigenvectors \(\mathbf{v}\). 3. **Construct the General Solution**: General solution will be of the form \(x(t) = c_1 e^{\lambda_1 t} \mathbf{v}_1 + c_2 e^{\lambda_2 t} \mathbf{v}_2\), where \(\lambda_1, \lambda_2\) and \(\mathbf{v}_1, \mathbf{v}_2\) are the eigenvalues and corresponding eigenvectors, and \(c_1, c_2\) are arbitrary constants. --- Utilize this procedure to find the solutions for the matrices provided in problems (a) and (b). If additional support or graphical descriptions are necessary, consult supplementary learning materials or a tutor.
Here is the transcription of the text from the provided image for educational purposes:

---

**(c) \( \mathbf{A} = \begin{bmatrix} -2 & -1 \\ 4 & 2 \end{bmatrix} \).**

---

In the above equation, matrix \( \mathbf{A} \) is given as a 2x2 matrix with the elements arranged in two rows and two columns. The top-left element of the matrix is -2, top-right is -1, bottom-left is 4, and bottom-right is 2.

Such matrices are commonly used in linear algebra to perform various operations such as matrix multiplication, finding determinants, and solving systems of linear equations.
Transcribed Image Text:Here is the transcription of the text from the provided image for educational purposes: --- **(c) \( \mathbf{A} = \begin{bmatrix} -2 & -1 \\ 4 & 2 \end{bmatrix} \).** --- In the above equation, matrix \( \mathbf{A} \) is given as a 2x2 matrix with the elements arranged in two rows and two columns. The top-left element of the matrix is -2, top-right is -1, bottom-left is 4, and bottom-right is 2. Such matrices are commonly used in linear algebra to perform various operations such as matrix multiplication, finding determinants, and solving systems of linear equations.
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