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3. For each of the following sequences, prove, using an ɛ,no argument that the sequence converges to the given limit p; that is, given ɛ > 0, determine no such that |pn– p| < ɛ for all n > no- Зп+5 2n+7 } ;P = (b) {},p= } 6n- (e) {},p = } n²+1 2n2 (d) {1-"},p=1 (-1)" (e) {/n+I-\m},p = 0

3. For each of the following sequences, prove, using an ɛ,no argument that the sequence converges to the given limit p; that is, given ɛ > 0, determine no such that |pn– p| < ɛ for all n > no- Зп+5 2n+7 } ;P = (b) {},p= } 6n- (e) {},p = } n²+1 2n2 (d) {1-"},p=1 (-1)" (e) {/n+I-\m},p = 0

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 64E
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3. For each of the following sequences, prove, using an ɛ,no argument that the sequence converges to the given limit p; that is, given ɛ > 0, determine no such that |Pn – p| < E for all n > no- (a) {},p= Зп+5 2n+7 (b) {},p= } 2n+5 6n- (e) {},p = } (d) {1–},p=1 n²+1 2n2 (e) {Vn+1-\m},p=0
Transcribed Image Text:3. For each of the following sequences, prove, using an ɛ,no argument that the sequence converges to the given limit p; that is, given ɛ > 0, determine no such that |Pn – p| < E for all n > no- (a) {},p= Зп+5 2n+7 (b) {},p= } 2n+5 6n- (e) {},p = } (d) {1–},p=1 n²+1 2n2 (e) {Vn+1-\m},p=0
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