3. For each of the following code fragments (each box is a separate code fragment), indicate what the program outputs or write error if it would crash or has a syntax error that prevents it from running. items = [1, 2, 3] if 2 in items: print('yes') print('no') else: items list (range (1, 5)) for x in items: print (x, end=' ') if x == 3: break items.append (0) print (items) items = [1, 2] + ['a', 'b'] print (2 items)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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## Code Fragment Analysis

### Problem Statement:
For each of the following code fragments (each box is a separate code fragment), indicate what the program outputs or write `error` if it would crash or has a syntax error that prevents it from running.

---

### Code Fragment 1:
```python
items = [1, 2, 3]
if 2 in items:
    print('yes')
else:
    print('no')
```
**Output:**  
`yes`

**Explanation:**  
This fragment checks if the number `2` is in the `items` list. Since `2` is present, it prints `yes`.

---

### Code Fragment 2:
```python
items = list(range(1, 5))
for x in items:
    print(x, end=' ')
    if x == 3:
        break
items.append(0)
print(items)
```
**Output:**  
`1 2 3`  
`[1, 2, 3, 4, 0]`

**Explanation:**  
- The list `items` is initialized with numbers from `1` to `4` using `range(1, 5)`.
- The `for` loop prints each number until it reaches `3`, then breaks out of the loop.
- After the loop, `0` is appended to `items`, resulting in `[1, 2, 3, 4, 0]`, which is printed.

---

### Code Fragment 3:
```python
items = [1, 2] + ['a', 'b']
print(2 * items)
```
**Output:**  
`[1, 2, 'a', 'b', 1, 2, 'a', 'b']`

**Explanation:**  
- The `items` list is a concatenation of `[1, 2]` and `['a', 'b']`, resulting in `[1, 2, 'a', 'b']`.
- Multiplying this list by `2` repeats its elements, creating `[1, 2, 'a', 'b', 1, 2, 'a', 'b']`.
Transcribed Image Text:## Code Fragment Analysis ### Problem Statement: For each of the following code fragments (each box is a separate code fragment), indicate what the program outputs or write `error` if it would crash or has a syntax error that prevents it from running. --- ### Code Fragment 1: ```python items = [1, 2, 3] if 2 in items: print('yes') else: print('no') ``` **Output:** `yes` **Explanation:** This fragment checks if the number `2` is in the `items` list. Since `2` is present, it prints `yes`. --- ### Code Fragment 2: ```python items = list(range(1, 5)) for x in items: print(x, end=' ') if x == 3: break items.append(0) print(items) ``` **Output:** `1 2 3` `[1, 2, 3, 4, 0]` **Explanation:** - The list `items` is initialized with numbers from `1` to `4` using `range(1, 5)`. - The `for` loop prints each number until it reaches `3`, then breaks out of the loop. - After the loop, `0` is appended to `items`, resulting in `[1, 2, 3, 4, 0]`, which is printed. --- ### Code Fragment 3: ```python items = [1, 2] + ['a', 'b'] print(2 * items) ``` **Output:** `[1, 2, 'a', 'b', 1, 2, 'a', 'b']` **Explanation:** - The `items` list is a concatenation of `[1, 2]` and `['a', 'b']`, resulting in `[1, 2, 'a', 'b']`. - Multiplying this list by `2` repeats its elements, creating `[1, 2, 'a', 'b', 1, 2, 'a', 'b']`.
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