3. For each of the following code fragments (each box is a separate code fragment), indicate what the program outputs or write error if it would crash or has a syntax error that prevents it from running. items = [1, 2, 3] if 2 in items: print('yes') print('no') else: items list (range (1, 5)) for x in items: print (x, end=' ') if x == 3: break items.append (0) print (items) items = [1, 2] + ['a', 'b'] print (2 items)
3. For each of the following code fragments (each box is a separate code fragment), indicate what the program outputs or write error if it would crash or has a syntax error that prevents it from running. items = [1, 2, 3] if 2 in items: print('yes') print('no') else: items list (range (1, 5)) for x in items: print (x, end=' ') if x == 3: break items.append (0) print (items) items = [1, 2] + ['a', 'b'] print (2 items)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![## Code Fragment Analysis
### Problem Statement:
For each of the following code fragments (each box is a separate code fragment), indicate what the program outputs or write `error` if it would crash or has a syntax error that prevents it from running.
---
### Code Fragment 1:
```python
items = [1, 2, 3]
if 2 in items:
print('yes')
else:
print('no')
```
**Output:**
`yes`
**Explanation:**
This fragment checks if the number `2` is in the `items` list. Since `2` is present, it prints `yes`.
---
### Code Fragment 2:
```python
items = list(range(1, 5))
for x in items:
print(x, end=' ')
if x == 3:
break
items.append(0)
print(items)
```
**Output:**
`1 2 3`
`[1, 2, 3, 4, 0]`
**Explanation:**
- The list `items` is initialized with numbers from `1` to `4` using `range(1, 5)`.
- The `for` loop prints each number until it reaches `3`, then breaks out of the loop.
- After the loop, `0` is appended to `items`, resulting in `[1, 2, 3, 4, 0]`, which is printed.
---
### Code Fragment 3:
```python
items = [1, 2] + ['a', 'b']
print(2 * items)
```
**Output:**
`[1, 2, 'a', 'b', 1, 2, 'a', 'b']`
**Explanation:**
- The `items` list is a concatenation of `[1, 2]` and `['a', 'b']`, resulting in `[1, 2, 'a', 'b']`.
- Multiplying this list by `2` repeats its elements, creating `[1, 2, 'a', 'b', 1, 2, 'a', 'b']`.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2d13e652-9219-41ff-a3a4-ec9d64bc6f59%2F9edfe9eb-928e-4c43-bf3b-5895e0ae304c%2Fhcy362p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Code Fragment Analysis
### Problem Statement:
For each of the following code fragments (each box is a separate code fragment), indicate what the program outputs or write `error` if it would crash or has a syntax error that prevents it from running.
---
### Code Fragment 1:
```python
items = [1, 2, 3]
if 2 in items:
print('yes')
else:
print('no')
```
**Output:**
`yes`
**Explanation:**
This fragment checks if the number `2` is in the `items` list. Since `2` is present, it prints `yes`.
---
### Code Fragment 2:
```python
items = list(range(1, 5))
for x in items:
print(x, end=' ')
if x == 3:
break
items.append(0)
print(items)
```
**Output:**
`1 2 3`
`[1, 2, 3, 4, 0]`
**Explanation:**
- The list `items` is initialized with numbers from `1` to `4` using `range(1, 5)`.
- The `for` loop prints each number until it reaches `3`, then breaks out of the loop.
- After the loop, `0` is appended to `items`, resulting in `[1, 2, 3, 4, 0]`, which is printed.
---
### Code Fragment 3:
```python
items = [1, 2] + ['a', 'b']
print(2 * items)
```
**Output:**
`[1, 2, 'a', 'b', 1, 2, 'a', 'b']`
**Explanation:**
- The `items` list is a concatenation of `[1, 2]` and `['a', 'b']`, resulting in `[1, 2, 'a', 'b']`.
- Multiplying this list by `2` repeats its elements, creating `[1, 2, 'a', 'b', 1, 2, 'a', 'b']`.
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