3. Find the force reactions, Rx, Ry, Rz, and the couple reactions, Cx, Cy, Cz at the base of the advertising sign shown below. The sign weighs 200 lb and the pole weighs 500 lb. 2 ft 10 ft 4 ft 2.5 ft 1 ft 250 lb (Resultant of pressure from wind)

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter2: Basic Operations With Force Systems
Section: Chapter Questions
Problem 2.83P: A 15-lb force acts at point A on the high-pressure water cock. Replace this force with (a) a force...
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3. Find the force reactions, Rx, Ry, Rz, and the couple reactions, Cx, Cy, Cz at the base of the advertising sign shown
below. The sign weighs 200 lb and the pole weighs 500 lb.
2 ft
10 ft
4 ft
2.5 ft
1 ft
250 lb
(Resultant
of pressure
from wind)
Transcribed Image Text:3. Find the force reactions, Rx, Ry, Rz, and the couple reactions, Cx, Cy, Cz at the base of the advertising sign shown below. The sign weighs 200 lb and the pole weighs 500 lb. 2 ft 10 ft 4 ft 2.5 ft 1 ft 250 lb (Resultant of pressure from wind)
N
y
X
Used with permission from "Engineering Mechanics: Statics," McGill/King, 4th Ed., 2003
O a. Rx = -2502 lb; Ry=-7003 lb; Rz=0
Cx=-4002 lb.ft; Cy=625 lb.ft; Cz=2250 lb.ft
O b. Rx = 2502 lb; Ry=7003 lb; Rz=0
Cx=-4002 lb.ft; Cy=6253 lb.ft; Cz=2250 lb.ft
O c. Rx=2502 lb; Ry=7003 lb; Rz = 0
Cx = 400î lb.ft; Cy = -625ĵ lb.ft; Cz= -2250k lb.ft
d. None of the above
Transcribed Image Text:N y X Used with permission from "Engineering Mechanics: Statics," McGill/King, 4th Ed., 2003 O a. Rx = -2502 lb; Ry=-7003 lb; Rz=0 Cx=-4002 lb.ft; Cy=625 lb.ft; Cz=2250 lb.ft O b. Rx = 2502 lb; Ry=7003 lb; Rz=0 Cx=-4002 lb.ft; Cy=6253 lb.ft; Cz=2250 lb.ft O c. Rx=2502 lb; Ry=7003 lb; Rz = 0 Cx = 400î lb.ft; Cy = -625ĵ lb.ft; Cz= -2250k lb.ft d. None of the above
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