3. Find an open cover of (x:x>0} with no finite subcover.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Transcribed Image Text:**Problem 33**: Find an open cover of \(\{x : x > 0\}\) with no finite subcover.
*Explanation*:
The task is to construct an open cover for the set of positive real numbers, \(\{x : x > 0\}\), such that no finite subset of this cover can also serve as a cover for the same set.
To achieve this, consider the set of open intervals \( \left(\frac{1}{n}, n\right) \) for all natural numbers \( n \). Each interval \( \left(\frac{1}{n}, n\right) \) is an open set that contributes to the cover of the set \(\{x : x > 0\}\).
- The union of all such intervals as \( n \) ranges over the natural numbers covers all positive real numbers because for any positive \( x \), you can find a natural number \( n \) such that \( x \) falls within the interval \( \left(\frac{1}{n}, n\right) \).
- If we take only a finite subset of this cover, say \( \left(\frac{1}{n_1}, n_1\right), \left(\frac{1}{n_2}, n_2\right), \ldots, \left(\frac{1}{n_k}, n_k\right) \), then there will be positive real numbers less than \( \frac{1}{n_m} \) for some maximum \( n_m \) that are not covered.
Therefore, this provides an illustration of an open cover with no finite subcover, demonstrating the nature of the set of positive real numbers.
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