3. Find all the values of x which satisfy the equation: (3 + x) (2-x) 10 5 = 48 (1-x) 2 (4 + x) -X

Q: If Q(x) = 7x - 1, find Q(- 9). Q(- 9) =

A:

Q: If x? + 6x – 59 = (x + A)² – B² , then the value of A is

A:

Q: x2 + 8x + 16 = 0, then what is x?

A: The given equation,              x2+8x+16=0

Q: If y =(3x)2 + 17 when x = -2 what is y

A: That's easy, just substitute value of x and you are done.

Q: (3x + 2)(x - 5) = 28

A: (3x + 2)(x - 5) = 28  => 3x^2 -15x +2x -10 = 28  => 3x^2 -13x - 10 -28 = 0  => 3x^2 -13x…

Q: y = -x - 5x + 6 and y = (x + 1)2 - 2 |

A:

Q: Find (f 9)and indicate the domain of the quotient F(x)=5x*-20x and glx) = 3x²-1ax. %3D

A:

Q: (x+8)2=7

A: Given: (x+8)2=7

Q: 2sqrt(x-1)=16

A:

Q: Find x³-4x² + 40x+127 (x²+25)(x − 4)² - I da

A:

Q: is 3(x- 3x-1): =- 3x -3-4

A: Given :- 3x-1=-6

Q: Find the Lim(4 ズ→ス ズ-2

A:

Q: If Q(x) = 6x - 1, find Q(- 7). 2 Q(- 7) =

A: The objective of the question find the the value of the function at x=-7.

Q: 3. (x²-x+6)÷( x- 3)

A: Here we have to divide it.

Q: Put the equation y = x² - 10x + 21 into the form y = (x - h)²+k:

A:

Q: Given 3( x + 4) = 30 then x =

A: Given equation is               3(x+4)=30 now we are dividing by 3 on both sides  then    x+4=10

Q: Evaluate (x2x+Idx

A:

Q: Evaluate 3x+5(y+3) when x is 1 less than the quotient of y and 3, and y=18

A: Given,

Q: x(x - 2) = 9

A:

Q: (7x + 9)" 16

A:

Q: If x = 4, what is the value of x(17 - x)?

A: Given  X = 4

Q: Hi.  I need help.   (1/x-2)+(3/x+3)=4/x2+x-6

A: We have to prove both the sides

Q: If 6 is substituted for x in the equation2(x - 3) - 17 = 13 - 3(x + 2),is the resulting statement…

A: Given Data The equation is 2(x-3)-17=13-3(x+2).   Substitute the values in the given left-hand side…

Q: da 2 (x4 – 6x бх" + 9)

A:

Q: -3x(x-3y+7)

A: To solve -3x(x-3y+7)

Q: x" -2x +x= 15; x (0) = 7, x (0) = -16 hand written plz

A: Given equation is x''-2x'+x=15   Also given x(0)=7,   x'(0)=-16   To Solve: x(t)