3. Examine the reaction mechanism found below: Step 1: HCI + S₂ + Brz➜ HS₂BrCl + Br Step 2: HCl + HS₂BrCl+Br → 2HSCI + Brz Step 3: 2HCI + 2HSCI → 2H₂S + 2Cl₂ (slow) (fast) (fast) a. Draw a circle around any reaction intermediates. b. Draw a box around any species that can be considered a catalyst. c. In the box below, provide the overall equation for this process. Overall Equation: d. Calculate the rate law equation for this mechanism and write it in the box below.

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Chapter1: Chemical Foundations
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3. Examine the reaction mechanism found below:
Step 1: HCI + S₂ + Brz➜ HS₂BrCl + Br
Step 2: HCl + HS₂BrCl+Br➜ 2HSCI
Step 3: 2HCI + 2HSC1 → 2H₂S + 2Cl2
+ Br₂
(slow)
(fast)
(fast)
a. Draw a circle around any reaction intermediates.
b. Draw a box around any species that can be considered a catalyst.
c. In the box below, provide the overall equation for this process.
Overall Equation:
Rate Law:
d. Calculate the rate law equation for this mechanism and write it in the box
below.
Transcribed Image Text:3. Examine the reaction mechanism found below: Step 1: HCI + S₂ + Brz➜ HS₂BrCl + Br Step 2: HCl + HS₂BrCl+Br➜ 2HSCI Step 3: 2HCI + 2HSC1 → 2H₂S + 2Cl2 + Br₂ (slow) (fast) (fast) a. Draw a circle around any reaction intermediates. b. Draw a box around any species that can be considered a catalyst. c. In the box below, provide the overall equation for this process. Overall Equation: Rate Law: d. Calculate the rate law equation for this mechanism and write it in the box below.
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